Use the hypergeometric distribution.
M=number of Men=5
F=number of women=4
m=number of men elected=2
f=number ow women elected=2.
Assuming equal chance to get elected, then
P(2M,2F)=C(M,m)*C(F,f)/C(M+F,m+f)
=C(5,2)*C(4,2)/C(9,4)
=10*6/126
=10/21
Reference: Hypergeometric distribution.
True...............................................................
65 x6 = 390
80 x 3= 240
390+240 = 630
Answer: 127^9 so 8594754748609400000
Step-by-step explanation: i’m not sure but 4+6 (7x3)-3 = 127 127^9
