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LenKa [72]
3 years ago
9

What solutions do these equations have?

Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

A.One solution

B.infinite solution

C.No solution

D.One solution

Step-by-step explanation:

A.7y+21=5y+8  so y=-13/2

B.10+6x=10+6x  x belongs to all real numbers

C.2x+5 and 2x+7 The leftside doesn't equal to the rightside

D.2x=12 x=6 One solution

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Step-by-step explanation:

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Here are two sets of numbers, a and b. Set a :200,104,100,160. Set b: 270,400,483,300, x. Mean of set a: mean of set b= 3:8. Wor
LenKa [72]

Given:

The given sets are:

Set a : 200, 104, 100, 160.

Set b: 270, 400, 483, 300, x.

Mean of set a: mean of set b= 3:8

To find:

The value of x.

Solution:

Formula for mean:

Mean=\dfrac{\text{Sum of observations}}{\text{Number of observation}}

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Mean=141

The mean of set of b is:

Mean=\dfrac{270+400+483+300+x}{5}

Mean=\dfrac{1453+x}{5}

Mean=\dfrac{1453+x}{5}

It is given that,

Mean of set a: mean of set b= 3:8

\dfrac{141}{\dfrac{1453+x}{5}}=\dfrac{3}{8}

\dfrac{705}{1453+x}=\dfrac{3}{8}

8\times 705=3\times (1453+x)

5640=4359
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Isolate the variable x.

5640-4359
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1281
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Divide both sides by 3.

\dfrac{1281}{3}
=x

427
=x

Therefore, the value of x is 427.

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Step-by-step explanation:

it's width is 6

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