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2 years ago

Help me find the value of W

Mathematics

1 answer:

Mama L [17]2 years ago

3 0

Answer:

what grade is this?

Step-by-step explanation:

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Identify a negative coterminal angle to 480°

Lisa [10]

Step-by-step explanation:

here's the answer to your question

8 0

2 years ago

16/m=2 Solve and write Divoson Equations

ycow [4]

M=8 this multiply of two it is easy

4 0

3 years ago

jamie wants to run a total of 9 miles thid week. so far, she has run 4 5/8 miles. use the equation 4 5/8 + r = 9. please help m

____ [38]

Answer:

$r=4\frac{3}{8}$

Step-by-step explanation:

Given the following question:

$4\frac{5}{8} +r=9$

Rewrite the expression to find the value of r:

$9-4\frac{5}{8}$

Subtract by finding the common denominator:
$9-4\frac{5}{8}$
$9=\frac{9}{1}$
$4\frac{5}{8} =8\times4=32+5=37=\frac{37}{8}$
$\frac{9}{1} -\frac{37}{8}$
$\frac{9}{1} \times8=\frac{72}{8}$
$\frac{37}{8} \times1=\frac{37}{8}$
$\frac{72}{8} -\frac{37}{8}$
$72-37=35$
$=\frac{35}{8}$
$\frac{35}{8} =35\div8=4\frac{3}{8}$
$r=4\frac{3}{8}$
$4\frac{5}{8} +4\frac{3}{8} =9$

Hope this helps.

4 0

1 year ago

the ratio of the number of shaded sections to the number of unshaded sections is 4 to 2 what is the value of the ratio of the nu

8090 [49]

Answer:

erxytfgnb

Step-by-step explanation:

3 0

2 years ago

A package of 10 batteries is checked to determine if there are any dead batteries. Four batteries are checked. If one or more ar

frutty [35]

Answer:

There is a probability of 76% of not selling the package if there are actually three dead batteries in the package.

Step-by-step explanation:

With a 10-units package of batteries with 3 dead batteries, the sampling can be modeled as a binomial random variable with:

n=4 (the amount of batteries picked for the sample).
p=3/10=0.3 (the proportion of dead batteries).
k≥1 (the amount of dead batteries in the sample needed to not sell the package).

The probability of having k dead batteries in the sample is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

Then, the probability of having one or more dead batteries in the sample (k≥1) is:

$P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{4}{0} p^{0}q^{4}=1*1*0.7^4=0.2401\\\\\\P(x\geq1)=1-0.2401=0.7599\approx0.76$

8 0

2 years ago