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frutty [35]
3 years ago
14

Write in slope intercept form an equation of the line that passes through the given points

Mathematics
2 answers:
Tpy6a [65]3 years ago
4 0

Answer:

The desired equation is y = x + 8.

Step-by-step explanation:

As we move right from (-2,6) to (4,12), x increases by 6 and y also increases by 6.  Thus, the slope, m, m = rise / run, is m = 6/6, or just m = 1.

Start with the slope intercept form y = mx + b.  Since m = 1, we now have y = x + b.  Subbing 4 for x, 12 for y, we can find b:  12 = 4 + b.  Thus, b = 8.

The desired equation is y = x + 8.

nevsk [136]3 years ago
3 0

Answer:

The answer to your question is y=1x+8

Step-by-step explanation: We already know that the slope formula is:

m=\frac{y2-y1}{x2-x1}

Substitute the values to find the slope

m= 12-6/4-(-2)

m= 6/4+2

m= 6/6

m=1, so, therefore, the slope is 1

And the y-intercept would be 8

Hope this helps and Please mark my answer as the brainliest

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The value of a_{5} is 2500, when a_{1}=4 and 5a_{n-1}.

Given that, a_{1}=4 and 5a_{n-1}.

We need to find the value of a_{5}.

<h3>What is an arithmetic sequence?</h3>

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of a_{5} :

a_{2} =5a_{2-1}=5a_{1}=5 \times4=20

a_{3} =5a_{3-1}=5a_{2}=5 \times20=100

a_{4} =5a_{4-1}=5a_{3}=5 \times100=500

a_{5} =5a_{5-1}=5a_{4}=5 \times500=2500

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