1.3-slope
6/3 just divide if you need to put it in a decimal-A
6/9 again you can just divide to get the decimal-green line
7/12-a the graph
-6/4 -b
Answer:
8w^2 I don't know why it is not on here, but I put it in an algebra calculator and everything. Good luck. :)
Step-by-step explanation:
Simply the radicals by multiplying and taking square roots.
2![\sqrt[4]{8w^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B8w%5E3%7D)
* ![\sqrt[4]{32w^5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B32w%5E5%7D)
= 2 *2w![\sqrt[4]{2w}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2w%7D)
= 4w![\sqrt[4]{16w^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16w%5E4%7D)
=4w(2w)
=
Answer is 3 seconds
When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)
s = -16t^2 + 48t
s = 0, solve for t
0 = -16t^2 + 48t
0 = t ( -16t + 48)
0 = 16t ( - t + 3)
now you have two equation
0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)
0 = 16 t
0 = t ( you know its false, because time = 0)
You are left with
0 = -t + 3
t = 3
It takes 3 seconds for the bullet to return to the ground.
// Hope this helps.
Out of 5 cards in the bag ...
-- There are 2 even numbers . . . 2 and 4 .
-- There are 3 odd numbers . . . 1, 3, and 5 .
So EITHER time, the probability of pulling an even number is 2/5 ,
and the probability of pulling an odd number is 3/5 .
The probability of pulling an even number the first time
AND an odd number the second time is
(2/5) x (3/5) = 6/25 = <em>24%</em> .
Answer:
128√5/3 mm³
Step-by-step explanation:
Since we are not told what to find, we can as well look for the volume of the pyramid
Volume of a square pyramid: V = (1/3)a²h
a is the side length of the square
h is the height of the pyramid
Given
a = 8mm
l² = (a/2)² + h²
l² = (a/2)² + h²
6² = (8/2)² + h²
h² = 6² - 4²
h² = 36 - 16
h² = 20
h = √20
Volume of a square pyramid = (1/3)*8²*√20
Volume of a square pyramid = 1/3 * 64 * 2√5
Volume of a square pyramid = 128√5/3 mm³
