Given=
length of the segment AD is 28 cm
distance between the midpoints of segments AB and CD is 16 cm
find out length of BC
To proof
AD = 28 cm
let the midpoint of the AB is E.
let the midpoint of the CD is F.
E & F are the midpoints i.e these points divide AB & CD in two equal parts.
Let BC = z
Let AE = EB = x ( E is midpoint)
Let CF = FD = y (F is midpoint)
the equation becomes
2x + 2y + z = 28
x + y + z = 16
mulitipy above equation by 2
we get
2x + 2y + 2z = 32
thus solving the equations
2x + 2y + 2z = 32
2x + 2y + z = 28
we get
z = 4 cm
i.e BC = 4 cm
Hence proved
Answer:
A.) x / 3 = 12 ----> x = 12(3) ----><em> </em><em>x = 36</em>
B.) 2x + 3 = 20 ----> 2x = 17 ----> x = 17/2
C.) 4/3x = 10/3 ----> x = 10/3 x 3/4 ----> x = 30/12 = 5/2
D.) -4x = -24 ----> x = -24/-4 ----> x = 6
E.) 2(x-4) = 10 ----> 2x - 8 = 10 ----> 2x = 18 ----> x = 9
F.) -0.5x + 1.1 = -2.9 ----> -0.5x = -4 ---> x = -4 / -0.5 ----> x = 8
$0.17x + $15 < 40 this is the awnser to this question. If you have any further questions plese contact me and I will be happy to explain anything.
30 and 13
x-y=17 and x+y=43
x=17+y and x=43-y, so 17+y=43-y
so y=13
43-13=30, so x=30 and y=13
Answer:
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Step-by-step explanation:
