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3 years ago

Which pair of triangles is congruent by AAS?

Mathematics

2 answers:

nlexa [21]3 years ago

5 0

c because they make the same size in shape

Mrac [35]3 years ago

4 0

The first one Hope it helps

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ruslelena [56]

A. 12pi meters.

Circumference = pi x diameter (pi x 12 = 12pi)
Diameter = 2 x radius (2 x 6 = 12)

8 0

3 years ago

There is less customer to the organization. Use the six steps in decision making process to solve the

OLEGan [10]

Answer:

Step 1: Define Desired Outcomes and Actions. ...

Step 2: Endorse the Process. ...

Step 4: Develop Alternatives or Options. ...

Step 5: Evaluate, Select, and Refine Alternative or Option. ...

Step 6: Finalize Documentation and Evaluate the Process.

Step-by-step explanation:

6 0

2 years ago

write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

#SPJ1

8 0

2 years ago

Two teachers purchase supplies for their classrooms.

inna [77]

Answer:

Cost of One Journal = $3.99

Cost of One pen = $0.59

Step-by-step explanation:

Let

Cost of One Journal = x

Cost of One pen = y

We can make equation from given statements.

Mr. Bowden purchases 18 journals and 40 pencils for $95.42.

$18x+40y=95.42$

Ms. Jacinto purchases 11 journals and 16 pencils for $53.33.

$11x+16y=53.33$

Now solving these equations to find the value of x

$18x+40y=95.42--eq(1)\\11x+16y=53.33--eq(2)$

Multiply eq(1) with 2 and eq(2) with 5

$36x+80y=190.84\\55x+80y=266.65\\-\:\:\:\:-\:\:\:\;\:\:\:\:\:\:\:-\\---------\\-19x=-75.81\\x=\frac{-75.81}{-19}\\x=3.99\\$

We get the value of x is: x=3.99

Now, putting value of x in equation 1 to find value of y.

$18x+40y=95.42\\18(3.99)+40y=95.42\\71.82+40y=95.42\\40y=95.42-71.82\\40y=23.6\\y=\frac{23.6}{40}\\y= 0.59$

So, we get the value of y: y = 0.59

Now, finding the costs:

Cost of One Journal = x = $3.99

Cost of One pen = y = $0.59

7 0

3 years ago

X-4=-11 please work problem out it’s homework need help

alisha [4.7K]

X-4=-11

move -4 to the other side

to get X by itself

sign changes from -4 to +4

X-4+4= -11+4

X= -11+4

Answer:

X= -7

5 0

3 years ago