We need to find thr rate of change (slope) of the line joining these two points ~
Slope of the line (m) joining the two points is 2 ~
<span>Ok. You would set up the problem like this: 32/x=64/100 and then cross multiply; 3200=64x; divide both sides by 64; x=50. Mary has 50 customers.</span>
The population is increasing greatly at a very fast rate compared to the rest of the data.
Answer:velocity=185 m/s
Step-by-step explanation:
So make k the subject of the formula by divide both by sqrt(x)
h= k × sqrt(x)
k=h/sqrt(x)
k=256 / sqrt(256)
k=256 / 16
k=16
So now substitute the value of k :
h= 16 × sqrt (x)
Then differentiate:
=(1/2 × sqrt(x))× 16
=16/(2×sqrt(x)
=8/sqrt(x)
Then
= 8/sqrt(x) × 370
=8/ sqrt(256) × 370
=8/16 × 370
velocity=185 m/s
Answer:
C. 325.
Step-by-step explanation:
The last term a5 = 85
a1 = 45
Sum of n terms = n/2 (a1 + l)
So here we have n = 5, a1 = 45 and the last term l = 85
= (5/2)(45 + 85)
= 5/2 * 130
= 325.
