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3 years ago

PLEASE HELP!!

Mathematics

1 answer:

Svetach [21]3 years ago

7 0

The rectangle is 28×34 and the two triangles are (1/2) 11 (28) and (1/2) (9)(34)

A = 28(34) + (1/2) 11 (28) + (1/2) (9)(34)

A = 1259

Answer: 1259 sq units

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Kaylis [27]

Answer:

none because they all correlate with each other and there are no obvious anomalies

Step-by-step explanation:

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3 years ago

Simplify the following expression by combining like terms.Select the most simplified expression 2w + 5w - 6 + 4w

KATRIN_1 [288]

Answer is 11w-6
Add all the like terms. So all with the w’s which is how I got 11 and then 6 stays the same hence the -6

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jek_recluse [69]

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3 years ago

11) Endpoint: (0,4), midpoint (-10, -3)<br> Find the endpoint?

earnstyle [38]

Answer:

(-20,-10)

Step-by-step explanation:

$( - 10 \: \: - 3) = ( \frac{0 + x}{2} \: \: \frac{4 + y}{2} )$

Solve for.x coordinate

$- 10 = \frac{0 + x}{2} \\ - 20 = 0 + x \\ x = - 20$

solve for y coordinate

$- 3 = \frac{4 + y}{2} \\ - 6 = 4 + y \\ - 10 = y$

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4 years ago

A market research team thinks that their new ad campaign is better than their old one. They used to be able to sell to 50% of th

andreev551 [17]

Answer:

a. The test statistic is 2 and we conclude that the new ad campaign is not signficantly better.

Step-by-step explanation:

They used to be able to sell to 50% of those who saw their ads. Test if the new campaign is better.

At the null hypothesis, we test is it is the same, that is, the proportion is the same.

$H_0: p = 0.5$

At the alternate hypothesis, we test if it is significantly better, that is, the proportion is above 50%.

$H_1: p > 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5$

They take a random sample of 100 potential buyers and find that they convinced 60 of these people to buy their product.

This means that $n = 100, X = \frac{60}{100} = 0.6$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.6 - 0.5}{\frac{0.5}{\sqrt{100}}}$

$z = 2$

The test statistic is 2.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.6, which is 1 subtracted the by p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

The p-value of the test is 0.0228 > 0.01, which means that we cannot conclude that the new ad campaign is signficantly better, so the correct answer is given by option A.

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3 years ago