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garri49 [273]
3 years ago
5

In the right triangle ABC with right angle at A , the inradius is 2cm. If the hypothenuse BC=10cm , determine the perimeter and

the are of the given triangle.
( please don’t use angle properties or trig )
Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0

Answer: 24cm

Step-by-step explanation:

Inradius = r

c = the hypothenuse

a & b = the other 2 sides of the triangle

Inradius formula: r = 1/2 * (a+b-c)

Plug in what we know.

2 = 1/2 * (a+b-10)

Multiply both sides by 2.

2*2 = 1/2 * (a+b-10) * 2

4 = a+b-10

Add 10 to both sides.

4+10 = a+b-10+10

14 = a+b

Perimeter formula: P=a+b+c

Plug in what we know

(remember a+b=14).

P=14 + 10

P = 24

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The selling price of a box of crackers is $1.75 You mark the crackers up to $2.54 . What is the markup percentage?
Aleks04 [339]

The markup percentage is 45.14%

Step-by-step explanation:

The given is:

  • The selling price of a box of crackers is $1.75
  • You mark the crackers up to $2.54

We need to find the markup percentage

The markup percentage = \frac{New-Old}{old} × 100%

∵ The selling price of a box of crackers is $1.75

∴ Old = 1.75

∵ You mark the crackers up to $2.54

∴ New = 2.54

- Substitute these values in the rule above

∵ The markup percentage = \frac{2.54-1.75}{1.75} × 100%

∴ The markup percentage = \frac{0.79}{1.75} × 100%

∴ The markup percentage = 0.4514 × 100%

∴ The markup percentage = 45.14%

The markup percentage is 45.14%

Learn more:

You can learn more about percentage in brainly.com/question/1834017

#LearnwithBrainly

8 0
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Answer:

Step-by-step explanation:

It is true that for any given odd integer, square of that integer will also be odd.

i.e if m is and odd integer then m^{2} is also odd.

In the given proof the expansion for (2k + 1)^{2} is incorrect.

By definition we know,

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Now, we know 4k^{2} and 4k will be even values

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