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2 years ago

ASAP! i need help it for a grade

Mathematics

2 answers:

kirill115 [55]2 years ago

5 0

Answer:

First box -3, 1

Second box -3, 7

Step-by-step explanation:

If they start at 4 on the y-axis, they can go down to 1 or go up to 7. Then we just add the -3 to the x axis.

vodomira [7]2 years ago

4 0

Answer:

(-3,7) and (-3,1)

Step-by-step explanation:

You would move the point up or down one (this is because you are moving on the y-axis) which would only change y leaving x alone as -3. This means you would either subtract 3 or add 3 to 4 which gives you 1 or 7.

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Can someone help me with this plz

allochka39001 [22]

Okay so any calculator works:

2 + 2 + 6 + 6 = 16

16 * 3.5 = 56 cm.

5 0

2 years ago

Read 2 more answers

PLEASE HURRY IM TIMED!!!

andriy [413]

Answer-

A. Brandon’s sound intensity level is 1/4th as compared to Ahmad’s.

Solution-

Given that, loudness measured in dB is

$L=10\log \frac{I}{I_0}$

Where,

I = Sound intensity,

I₀ = 10⁻¹² and is the least intense sound a human ear can hear

Given in the question,

I₁ = Intensity at Brandon's = 10⁻¹⁰

I₂ = Intensity at Ahmad's = 10⁻⁴

Then,

$L_1=10\log \frac{I_1}{I_0}=10\log \frac{10^{-10}}{10^{-12}}=10\log \frac{1}{10^{-2}}=10\log 10^{2}=2\times10\log 10=20$

$L_2=10\log \frac{I_2}{I_0}=10\log \frac{10^{-4}}{10^{-12}}=10\log \frac{1}{10^{-8}}=10\log 10^{8}=8\times10\log 10=80$

$\therefore \frac{L_1}{L_2} =\frac{20}{80} =\frac{1}{4}$

5 0

2 years ago

An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal. Find the force necessary to prevent the car fro

Misha Larkins [42]

Answer:

1931.7N

Step-by-step explanation:

We are told in the question that :

An auto ( a car) weighs = 2500 pounds

It s inclined at n horizontal Ange of 10°

We are asked to find the force that would prevents it from rolling down the street.

Since the unit for Force = Newton or kgm/s²

Step 1

Convert Weight in pounds to kg

1 pound = 0.453592kg

2500 pounds =

2500 pounds × 0.453592kg

= 1133.981kg

Step 2

Find the force that would prevents it from rolling down the street.

Force = Mass × Acceleration due to gravity × sin θ

Acceleration due to gravity = 9.81m/s

Force = 1133.981kg × 9.81 × sin 10°

Force = 1931.7237321 N

Approximately = 1931.7N

4 0

3 years ago

The coordinates of the vertices of □PQR are (-2,5), Q(-1,), and R(7,3). Determine whether □ PQR is a right triangle. Show Your W

alexdok [17]

Answer:

Slope of PQ

−

(

−

)

−

Slope of QR

−

(

−

)

Slope of RP

−

Since slopes PQ & PR,

−

, it's a right triangle

4 0

2 years ago

Two cylindrical containers, C and D, with different capacities are shown below. What is the total volume of liquid held in these

Zielflug [23.3K]

Answer:

Option D. (x + 4)(x + 1)

Step-by-step explanation:

From the question given above, the following data were obtained:

C = (6x + 2) L

D = (3x² + 6x + 9) L

Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:

Volume in C = ½C

Volume in C = ½(6x + 2)

Volume in C = (3x + 1) L

Volume in D = ⅓D

Volume in D = ⅓(3x² + 6x + 9)

Volume in D = (x² + 2x + 3) L

Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:

Volume in C = (3x + 1) L

Volume in D = (x² + 2x + 3) L

Total volume =?

Total volume = Volume in C + Volume in D

Total volume = (3x + 1) + (x² + 2x + 3)

= 3x + 1 + x² + 2x + 3

= x² + 5x + 4

Factorise

x² + 5x + 4

x² + x + 4x + 4

x(x + 1) + 4(x + 1)

(x + 4)(x + 1)

Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.

6 0

2 years ago