ASAP! i need help it for a grade

Mathematics

2 answers:

kirill115 [55]2 years ago

5 0

Answer:

First box -3, 1

Second box -3, 7

Step-by-step explanation:

If they start at 4 on the y-axis, they can go down to 1 or go up to 7. Then we just add the -3 to the x axis.

vodomira [7]2 years ago

4 0

Answer:

(-3,7) and (-3,1)

Step-by-step explanation:

You would move the point up or down one (this is because you are moving on the y-axis) which would only change y leaving x alone as -3. This means you would either subtract 3 or add 3 to 4 which gives you 1 or 7.

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**URGENT** PLEASE HELP WILL GIVE BRAINLIEST

Gnoma [55]

Answer:

they are both 0 since they would not appear on a graph

Step-by-step explanation:

6 0

3 years ago

Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0

Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

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Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

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$h(x)=\dfrac{1}{3}|x-6|+4$

Put the values of x to the equation of the function h(x):

$x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6$