Answer:
1/(11 x^(9/2) y^4 z^5)
or
sqrt(x)/ 11 x^5 y^4 z^5
Step-by-step explanation:
1/ sqrt(121x^9y^8z^10)
Lets simplify the denominator
sqrt(121x^9y^8z^10)
Break it into pieces
sqrt(121) sqrt(x^9) sqrt(y^8) sqrt(z^10)
11 sqrt (x^8) sqrt(x) y^4 z^5
11 x^4 y^4 z^5 * sqrt(x)
Putting this back in
1
----------------------------
11 x^4 y^4 z^5 * sqrt(x)
But we dont want a sqrt root in the denominator
Multiply by sqrt(x)/sqrt(x)
sqrt(x)
----------------------------
11 x^4 y^4 z^5 * sqrt(x) sqrt(x)
sqrt(x)
----------------------------
11 x^4 y^4 z^5 * x
sqrt(x)
----------------------------
11 x^5 y^4 z^5
Answer:
2.7
Step-by-step explanation:
I got it right
20×8=160
160×5=800
james earns $800 in one week.
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
