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german
2 years ago
7

Behavior (defense mechanisms)definition

Chemistry
1 answer:
Gekata [30.6K]2 years ago
7 0
A variety of usually unconscious mental processes used to protect oneself from shame, anxiety, loss of self-esteem, conflict, or other unacceptable feelings or thoughts, and including behaviors<span> such as repression, projection, denial, and rationalization.

(google)</span>
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Making the simplistic assumption that the dissolved NaCl(s) does not affect the volume
kvv77 [185]
*** 2 *** 
<span>if we assume volume NaCl + volume H2O = volume H2O.. i.e.. NaCl does not effect volume </span>

<span>therefore.. the units of.. </span>
<span>.. M = moles NaCl / L solution ≈ moles NaCl / L H2O </span>
<span>.. density = grams NaCl / L solution ≈ grams NaCl / L H2O </span>
<span>again.. that is our assumption </span>

<span>so we can readily see that </span>
<span>.. M = (1 mol NaCl / ___g NaCl) x (__g NaCl / L H2O) + 0 </span>
<span>ie.. </span>
<span>.. M = (1 mol NaCl / 58.5g NaCl) x density solution + 0 </span>

<span>so.. we would expect.. </span>
<span>.. m = 0.01709 mol / g </span>
<span>.. b = 0 </span>
3 0
3 years ago
Give the nuclear symbol for the isotope of silicon for which a=29? Enter the nuclear symbol for the isotope (e.G., 42he).
quester [9]

The mass number is the summation of number of proton and neutron present in a nucleus of an atom. For the neutral atom the number of positive charge (number of proton) must be equal to the number of electrons. The number of electrons present in an atom is the atomic number of the atom. The standard way to express the mass number (a) and atomic number (m) of a atom (say X) is x^{a}_{m}. Now for silicon number of electron or atomic number is 14. And the mass number (a) given 29. Thus the expression nucleus of silicon will be Si^{29}_{14}

7 0
3 years ago
The diameter of metal wire is often referred to by its American wire-gauge number. A 16 gauge-wire has a diameter of 0.05082 in.
lubasha [3.4K]

Answer:

length of wire = 38.82 m

Explanation:

∴ 16 gauge ≡ 0.05082 in * ( 2.54 cm/in ) = 0.12908 cm

∴ m spool = 1 Lb = 453.592 g

∴ ρ = 8.92 g/cm³

cross section area:

⇒ A = π*D²/4 = π*(0.12908)²/4 = 0.0131 cm²

⇒ L = ((453.592 g) *(cm³/8.92 g)) / ( 0.0131 cm² )

⇒ L = 3881.765 cm * ( m/100cm) = 38.82 m

8 0
3 years ago
18. How many moles of atoms are there in each of
Lelechka [254]

a) 1 mole of Ne

b) i/2 mole of Mg

c) 1570 moles of Pb.

d) 2.18125*10^-13 moles of oxygen.

                     

Explanation:

The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.

6.23*10^23= 1/ 6.23*10^23

                   = 1 mole

The number of moles calculated by Avogadro's number in 3.01*10^23 of  Mg

3.2*10^23=1/6.23*10^23

                = 1/2 moles of Pb.

Number of moles in 3.25*10^5 gm of lead.

atomic weight of Pb=

n=weight/atomic weight

  = 3.25*10^5/ 207

  = 1570 moles of Pb.

Number of moles 4.50 x 10-12 g O

number of moles= 4.50*10^-12/16

                            =  2.18125*10^-13 moles of oxygen.

3 0
3 years ago
Hello, can someone pls help me ty!​
Rudiy27

Answer:

The answer is A

Explanation:

4 0
3 years ago
Read 2 more answers
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