Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:

A. Chloroplasts
B. The cell wall and the vacuole
C. Vacuoles
D. The mitochondrion
Answer:
Mass by mass
Explanation:
Because it's telling only about mass in grams
A !.!.!.!.!.!!..!.!.!.!.!.!.!.!!.!..!!.!.!.!.!.!.!.!.!.!.!!.!.!.!.!
Answer:
0°C and 1 atm
Explanation:
This are the conditions of temperature and pressure defined by IUPAC as standard.
But also, the definition used by the NIST considerates a temrperature of 20°C and a pressure of 1 atm