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Ray Of Light [21]
3 years ago
15

What is the difference between breccia rock and conglomerate rock

Chemistry
1 answer:
Klio2033 [76]3 years ago
4 0
Breccia rocks and conglomerate rocks are said to be very similar rocks. They both are sedimentary rocks. Their difference lies on their shapes. For breccia rocks, large particles are angular in shape which is different from the conglomerate rocks where they are rounded.
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Please please help me please please
uranmaximum [27]

Answer: 1. A, 2.B, 3. D, 4. B, 5. C

Explanation:

i have P.E. too lol have a great day!

5 0
3 years ago
Why is oxygen diflouride a gas at room temperature?
atroni [7]

Answer:

Oxygen is a simple molecular structure, where individual oxygen atoms are bonded to each other by strong covalent bonds. Hence, a low amount of energy is required to overcome these weak forces and oxygen has a low boiling point. Therefore, at room temperature, oxygen is a gas. Oxygen difluoride is a colorless gas, condensable to a pale yellow liquid, with a slightly irritating odor. It is the most stable of the compounds of fluorine and oxygen, which include O,F,, O,F, and 0,F2 but nevertheless it is a strong oxidizing and fluorinating agent. Oxygen Difluoride is a colorless gas or a yellowish-brown liquid with a foul odor. Just to finally link Joseph's answer to the question, oxygen difluoride will thus change from liquid to solid state when chilled from -220°c to -230°c. The boiling point of oxygen is -182.96 degrees Celsius (under 1 standard atmosphere). This means at temperatures below that point, oxygen is a solid or a liquid, and at temperatures above that point, oxygen is a gas. So at -183 degrees Celsius, oxygen is a liquid.

Explanation:

3 0
3 years ago
Explain briefly how an infrared spectrometer works. Please help immediately!!! :(
artcher [175]
Infrared (IR) spectroscopy uses infrared radiation to excite the molecules of a compound and generates an infrared spectrum of the energy absorbed by a molecule as a function of the frequency or wavelength of light
3 0
3 years ago
How many grams of NaCl are needed to prepare 60 g of a 6.0% solution?
AlekseyPX

Answer:

3.6 grams of NaCl are needed

Explanation:

Percent solution are solutions whose concentrations are expressed in percentages. The amount(either weight or volume) of a solute is expressed as a percentage of the total weight or volume of solution. Percent solutions can either be expressed as  weight/volume % (wt/vol % or w/v %), weight/weight % (wt/wt % or w/w %), or volume/volume % (vol/vol % or v/v %).

A 6.0% wt/wt % solution contains 6 g of solute in 100 g of solution

Therefore, a 100 g solution contains 6.0 g of solute.

60 g of 6.0% solution will contain  60 g solution * 6.0 g solute/ 100 g solution

Mass of NaCl present =  3.6 g  of NaCl

3 0
3 years ago
If ch4 and c4h8 are released simultaneously at ends of a 50.0cm long glass tube, at what distance from the left end of the tube
Keith_Richards [23]

Answer:

They meet at the distance of 32.5 cm

Explanation:

The rate of diffusion is inversely proportional to the molar mass of gases.

If diffusion is represented as d and mass of gases as M. Then , rate is given as:

d=k\sqrt{\frac{1}{M}}

For , two gases

\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}

First , Calculate the ,molar mass of each gas :

CH4 = 1 (mass of C) + 4(mass of H)

= 1(12)+4(1)

= 12 + 4 = 16 gram

M1 = 16 gram

C4H8 = 4(mass of C) + 8(Mass of H)

= 4(12) + 8(1)

= 48 + 8

M2 = 56 grams

d1 is diffusion of CH4

d2 = diffusion of C4H8

\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}

\frac{d_{1}}{d_{2}}=\sqrt{\frac{56}{16}}

\frac{d_{1}}{d_{2}} = 1.87

This means CH4 diffuse 1.87 times faster than C4H8

Now, the mathematical part

If velocity of C4H8 = 1 cm/sec , then velocity of CH4 = 1.87 cm/sec

v1 = 1.87 cm/sec

v2 = 1 cm/sec

Let both meet at time "t". If distance travelled by CH4(s1) = x , then remaining(s2) distance (50-x) is travelled by C4H8

(see the attached image)

time =\frac{distance}{speed}

since both meet at same time so t = constant.

\frac{s1}{v1}=\frac{s2}{v2}

\frac{x}{1.87}\frac{50-x}{1.00}

on solving for x we get,

x = 17.42 cm

from the other side the distance is (50 - x)

= 50 - 17.42 = 32.5 cm

7 0
3 years ago
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