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AlekseyPX
3 years ago
6

Emission Vehicle Program Should automobile makers be made to adhere to quotas zero - emission vehicles set by states , even if t

he causes automakers to lose revenue ?
Chemistry
1 answer:
navik [9.2K]3 years ago
7 0

Answer: Zero-emission vehicles have no tailpipe emissions, no emissions from gasoline, and no emission-control systems, which deteriorate over time.

Explanation:

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How do we observe in experiments?
anyanavicka [17]

Answer:

by watching and writing down the information that is provided

Explanation:

6 0
3 years ago
What do The seven dots around fluorine represent
borishaifa [10]
The seven dots around flourine are the valence electrons
7 0
3 years ago
Calculate the amount of energy required to melt 500 g of ice at 0oc. (δhfus=5.96 kj/mole; δhfus is the energy required to melt i
marta [7]
When you want to melt an ice, you only need the latent energy of fusion, <span>δhfus. We use the given value, then multiply this with the given amount to determine the amount of energy. Since the energy is per mole basis, use the molar mass of ice which is 18 g/mol. The solution is as follows:

</span>ΔH = 5.96 kJ/mol * 1 mol/18 g * 500 g
<em>ΔH = 165.56 kJ</em><span>
</span>
3 0
3 years ago
Locate Lithium and oxygen on the periodic table. Briefly explain how these elements might combine to form a compound.
Mars2501 [29]
<span>Lithium atoms have one valence electron, where as oxygen atoms have six. Lithium atoms tend to give up their single valence electrons, and oxygen tends to gain two valence electrons from other atoms, like lithium. They do this so they will have filled valence shells.  hope this answers your question :)</span>
7 0
4 years ago
Read 2 more answers
What is the energy of a photon that emits a light of frequency 6.42 x 1014 Hz?<br><br>​
svetlana [45]

Answer:

Option B. 4.25×10¯¹⁹ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 6.42×10¹⁴ Hz

Energy (E) =?

Energy and frequency are related by the following equation:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

With the above formula, we can obtain the energy of the photon as follow:

Frequency (f) = 6.42×10¹⁴ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 6.42×10¹⁴

E = 4.25×10¯¹⁹ J

Thus, the energy of the photon is 4.25×10¯¹⁹ J

3 0
3 years ago
Read 2 more answers
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