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ASHA 777 [7]
3 years ago
13

Sketch the graph of the function.Label the Vertex y=-5x^2+10

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

See attached photo.

Step-by-step explanation:

y=-5x^2+10

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Pachacha [2.7K]
Lets simplify this first.
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6 0
3 years ago
Francesca had 20 dollars to spend on 3 gifts. She spent 8 1 4 dollars on gift A and 4 4 5 dollars on gift B. How much money did
Karo-lina-s [1.5K]

Answer:

Francesca had \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20} money left for gift C.

Step-by-step explanation:

Given:

Total money to spent on gift = $20

Money Spent on gift A = \$ 8\frac{1}{4}

\$ 8\frac{1}{4} can Rewritten as  \$\frac{33}{4}

Money Spent on gift A = \$\frac{33}{4}

Money Spent on gift B = \$ 4\frac{4}{5}

\$ 4\frac{4}{5} can Rewritten as  \$\frac{24}{5}

Money Spent on gift B = \$\frac{24}{5}

We need To find the Money left for gift C.

Solution:

Money left for gift C can be calculated by subtracting Money Spent on gift A and Money Spent on gift B with Total Money spent on gifts.

Framing in equation form we get;

Money left for gift C = 20-\frac{33}{4}-\frac{24}{5}

Now taking LCM for making the denominator common we get;

Money left for gift C =\frac{20\times 20}{20}-\frac{33\times5}{4\times5}-\frac{24\times4}{5\times4}= \frac{400}{20}-\frac{165}{20}-\frac{96}{20}=\frac{400-165-96}{20} = \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20}

Hence Francesca had \$\frac{139}{20} \ \ OR \ \ \$6\frac{19}{20} money left for gift C.

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So, what I usually do is draw a division box, put the numerator (4.4) in and the denominator out and then do a normal division. <span />
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