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Pavel [41]
2 years ago
12

What is the area of this quadrilateral?

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
4 0

Answer:

The area is 40 square feet

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In how many ways can we seat 3 pairs of siblings in a row of 7 chairs, so that nobody sits next to their sibling
monitta

Answer:

1,968

Step-by-step explanation:

Let x₁ and x₂, y₁ and y₂, and z₁ and z₂ represent the 3 pairs of siblings, and let;

Set X represent the set where the siblings x₁ and x₂ sit together

Set Y represent the set where the siblings y₁ and y₂ sit together

Set Z represent the set where the siblings z₁ and z₂ sit together

We have;

Where the three siblings don't sit together given as X^c∩Y^c∩Z^c

By set theory, we have;

\left | X^c \cap Y^c \cap Z^c  \right | = \left | X^c \cup Y^c \cup Z^c  \right | =  \left | U  \right | - \left | X \cup Y \cup Z  \right |

\left | U  \right | - \left | X \cup Y \cup Z  \right | = \left | U  \right | - \left (\left | X \right | +  \left | Y\right | +  \left | Z\right | -  \left | X \cap Y\right | -  \left | X \cap Z\right | -  \left | Y\cap Z\right | +  \left | X \cap Y \cap Z\right | \right)

Therefore;

\left | X^c \cap Y^c \cap Z^c  \right | = \left | U  \right | - \left (\left | X \right | +  \left | Y\right | +  \left | Z\right | -  \left | X \cap Y\right | -  \left | X \cap Z\right | -  \left | Y\cap Z\right | +  \left | X \cap Y \cap Z\right | \right)

Where;

\left | U\right | = The number of ways the 3 pairs of siblings can sit on the 7 chairs = 7!

\left | X\right | = The number of ways x₁ and x₂ can sit together on the 7 chairs = 2 × 6!

\left | Y\right | = The number of ways y₁ and y₂ can sit together on the 7 chairs = 2 × 6!

\left | Z\right | = The number of ways z₁ and z₂ can sit together on the 7 chairs = 2 × 6!

\left | X \cap Y\right | = The number of ways x₁ and x₂ and y₁ and y₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | X \cap Z\right | = The number of ways x₁ and x₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | Y \cap Z\right | = The number of ways y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | X \cap Y \cap Z\right | = The number of ways x₁ and x₂,  y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 2 × 4!

Therefore, we get;

\left | X^c \cap Y^c \cap Z^c  \right | = 7! - (2×6! + 2×6! + 2×6! - 2 × 2 × 5! - 2 × 2 × 5! - 2 × 2 × 5! + 2 × 2 × 2 × 4!)

\left | X^c \cap Y^c \cap Z^c  \right | = 5,040 - 3072 = 1,968

The number of ways where the three siblings don't sit together given as \left | X^c \cap Y^c \cap Z^c  \right |  = 1,968

5 0
3 years ago
I NEED HELP ASAP PLEASE!!
Makovka662 [10]

Answer:

(2x-3) (2x+3)

zeros, x intercepts:  -3/2, 3/2

Step-by-step explanation:

4x^2 -9

We know the difference of squares is a^2 -b^2

This factors into (a-b) (a+b)

Let 4x^2 =a^2  

Taking the square root

2x =a

Let b^2 =9

Taking the square root

b= 3

(4x^2-9 ) = (2x-3) (2x+3)

To find the zeros, we set the equation equal to zero

(4x^2-9 ) = (2x-3) (2x+3) =0

Using the zero product property

2x-3 =0   and 2x+3 =0

2x-3+3 = 0+3                    2x+3-3 = 0-3

2x=3                                  2x=-3

Divide by 2

2x/2 = 3/2                               2x/2 = -3/2

x = 3/2                                       x = -3/2

These are the zeros of the equation (which are also the x intercepts)

8 0
3 years ago
Which statement is true regarding the graphed functions?
andreev551 [17]

There is no graph, so it is impossible to answer this question. I apologise.

7 0
3 years ago
Can someone tell me what’s the answer to this question pls and thank you I will give brainliest
WARRIOR [948]
<h3><u>Out of the four options, the letter B is a function.</u></h3>

A function cannot have an x value with two different listed y terms.

B is the only option that does not repeat x terms.

4 0
3 years ago
If f(x) = 3x + 7, find:<br> f(3) = [?]<br> Enter
Elan Coil [88]
F(3)= 16. Essentially, you need to substitute 3 for x, which would look like this: 3(3) + 7. Then, by using PEMDAS/the order of operations, multiply 3 by 3 to get 9, and then add 7 to get 16.
5 0
3 years ago
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