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Vikki [24]
3 years ago
11

Help again please !

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
6 0
The answer is C.

y = -3x + 2
y = -3x + 4

-3x + 2 = -3x + 4
         2 ≠ 4
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What is the perimeter of a half circle with a radius 22cm .round your answer to the nearest whole number
Korolek [52]

Answer:

113.115 cm

Step-by-step explanation:

<u>Formula:</u>

C = 2πr

<u>Given:</u>

Radius: 22 cm

Diameter: 44 cm

The perimeter of a semicircle is the sum of half of the circumference of the circle and its diameter.

Simply plug in your numbers to find the circumference first.

C = 2π(22)

C = 44π cm or 138.23 cm

Then, divide the circumference in half, and add your diameter.

Perimeter = (44π/2) + 44 = 113.115 cm

6 0
3 years ago
Given: f(x) = X^2 - 3 and g(x) = X + 1 The composite function g°f is:_______.
LenKa [72]

Answer:

x² - 2

Step-by-step explanation:

To obtain (g ○ f)(x), substitute x = f(x) into g(x), that is

g(x² - 3)

= x² - 3 + 1

= x² - 2

8 0
3 years ago
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The density of a substance is the mass of the substance per unit of volume. The density of the element Americium is inversely pr
Viktor [21]

Answer:

(3,4)

Step-by-step explanation:

7 0
3 years ago
Gavin and Caleb are playing baseball. When Gavin hits the baseball it is projected upward from ground level over Caleb's head wi
KengaRu [80]
The answer is 1434 hope this helps
6 0
3 years ago
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Use f’( x ) = lim With h ---&gt; 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²
beks73 [17]
<h2>Answer:</h2>

The derivative of the function f(x) is:

                 f'(x)=-2x

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

f(x)=5-x^2

We have:

f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)

( Since,

(a+b)^2=a^2+b^2+2ab )

Hence, we get:

f(x+h)=5-x^2-h^2-2xh

Also, by using the definition of f'(x) i.e.

f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}

Hence, on putting the value in the formula:

f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x

      Hence, the derivative of the function f(x) is:

          f'(x)=-2x

3 0
3 years ago
Read 2 more answers
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