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FromTheMoon [43]
3 years ago
13

The John Jay Theater Dept has tickets at $6 for adults, $4 for teachers, and $2 for students. A total of 280 tickets were sold f

or one showing with a total revenue of $1010. If the number of adult tickets sold was twice the number of teacher tickets, how many of each type of ticket were sold for the showing?
Mathematics
1 answer:
OleMash [197]3 years ago
5 0

Answer:

number of adults tickets sold = x = 90

number of teachers tickets = y = 45

number of students tickets = z = 145

Step-by-step explanation:

Cost of tickets

Adults = $6

Teachers = $4

Students = $2

Total tickets sold = 280

Total revenue = $1010

Let

x = number of adults tickets

y = number of teachers tickets

z = number of students tickets

x + y + z = 280

6x + 4y + 2z = 1010

If the number of adult tickets sold was twice the number of teacher tickets

x = 2y

Substitute x=2y into the equations

x + y + z = 280

6x + 4y + 2z = 1010

2y + y + z = 280

6(2y) + 4y + 2z = 1010

3y + z = 280

12y + 4y + 2z = 1010

3y + z = 280 (1)

16y + 2z = 1010 (2)

Multiply (1) by 2

6y + 2z = 560 (3)

16y + 2z = 1010

Subtract (3) from (2)

16y - 6y = 1010 - 560

10y = 450

Divide both sides by 10

y = 450/10

= 45

y = 45

Substitute y=45 into (1)

3y + z = 280

3(45) + z = 280

135 + z = 280

z = 280 - 135

= 145

z = 145

Substitute the values of y and z into

x + y + z = 280

x + 45 + 145 = 280

x + 190 = 280

x = 280 - 190

= 90

x = 90

Therefore,

number of adults tickets sold = x = 90

number of teachers tickets = y = 45

number of students tickets = z = 145

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What is the largest number of pancakes that Benjamin can afford
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Answer:

See explanation

Step-by-step explanation:

Here is the complete question:

Benjamin decides to treat himself to breakfast at his favorite restaurant. He orders chocolate milk that costs $3.25. Then, he wants to buy as many pancakes as he can, but he wants his bill to be at most $30 before tax. The restaurant only sells pancakes in stacks of 4 pancakes for $5.50 . Let S represent the number of stacks of pancakes that Benjamin buys. What is the largest number of pancakes that Benjamin can afford?

Given:

Cost of chocolate milk = $3.25

Maximum bill that Benjamin wants before tax = $30

Cost of stack of 4 pancakes = $5.50

Let S be the number of stacks of pancakes that Benjamin buys

Solution:

Cost per stack of pancakes = $5.50  

Cost of S number of stacks of pancakes = S*5.50  = 5.50 S

So benjamin will spend money on 1 chocolate milk and S number of stacks of pancakes

Compute the total money spent by Benjamin:

Cost of chocolate milk + cost per stack of pancakes = 3.25 + 5.50 S

Maximum bill that Benjamin wants is $30 So,

The total money should be less than equal to the maximum bill that benjamin wants i.e. less than or equal to 30. So it is represented as:

3.25 + 5.50S ≤ 30  ----- (1)

Now using (1) we can find the largest number of pancakes that  Benjamin can afford :

3.25 + 5.50S ≤ 30

5.50S ≤ 30 - 3.25    

subtract 3.25 from 30

5.50S ≤ 26.75

Divide by 5.50

S ≤ 4.863636

S ≤ 4.86

S≤ 4 approx

Since the restaurant only sells pancakes in stacks of 4 pancakes so,

4 stacks = 4 *4 =  16

So the largest number of pancakes that Benjamin can afford are 16.

If we do not round off the the value stacks then we get:

4.86 stacks = 4.86 *4 =  19.44 pancakes

So the largest number of pancakes that Benjamin can afford are 19

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3 years ago
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