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2 years ago

Guided Practice

Mathematics

2 answers:

sveticcg [70]2 years ago

8 0

Answer:

Step-by-step explanation:

3x – 7 > – 1

3x > 6

x < 2

Alla [95]2 years ago

4 0

Answer:

Answer:

C. 5

Step-by-step explanation:

3x – 7 > – 1

Add 7 to each side

3x – 7+7 > – 1+7

3x> 6

Divide each side by 3

3x/3 >6/3

x >2

X must be greater than 2

Step-by-step explanation:

igoroleshko156

Genius

2K answers

3.1M people helped

Answer:

Step-by-step explanation:

Step 1: Subtract 7 from both sides

Step 2: Divide both sides by -3

Since you divided by a negative, you must flip the sign.

Answer: x<2

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3 years ago

Maths trig functions <br> please help

Nikitich [7]

1. According to the plots, the curves intersect when $x=90^\circ$ and $x=360^\circ$ .

We can confirm this algebraically.

$\sin(x) + 2 = -\cos(x) + 3$

$\sin(x) + \cos(x) = 1$

$\sqrt2 \sin\left(x + 45^\circ\right) = 1$

$\sin\left(x + 45^\circ\right) = \dfrac1{\sqrt2}$

$x + 45^\circ = \sin^{-1}\left(\dfrac1{\sqrt2}\right) + 360^\circ n \text{ or } x + 45^\circ = 180^\circ - \sin^{-1}\left(\dfrac1{\sqrt2}\right) + 360^\circ n$

(where $n$ is an integer)

$x + 45^\circ = 45^\circ + 360^\circ n \text{ or } x + 45^\circ = 135^\circ + 360^\circ n$

$x = 360^\circ n \text{ or } x = 90^\circ + 360^\circ n$

We get the two solutions we found in the interval [0°, 360°] with $n=1$ in the first case, and $n=0$ in the second case.

2. We have $\sin(x)=0$ when $x \in \{0^\circ, \pm 180^\circ, \pm360^\circ, \ldots\}$ . For the given plot domain [0°, 360°], this happens when $180^\circ < x < 360^\circ$ .