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3 years ago

Please help with this question! It’s Algebra Math 2

Mathematics

1 answer:

juin [17]3 years ago

3 0

Zero of 7 with a multiplicity of 3 means one factor is $(x-7)^3$

Zero of -1 with a multiplicity of 2 means one factor is $(x+1)^2$

Zero of 5 with a multiplicity of 1 means one factor is $(x-5)$

Multiplying, we get

$f(x) = (x-7)^3(x+1)^2(x-5)$

That's already in factored form so we leave it here.

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Remove the brackets and simplify

Komok [63]

Answer:

$5x - 7 {x}^{2} - {(2x)}^{2} \\ = ( {2}^{2} {x}^{2} ) - 7 {x}^{2} + 5x \\ = 4 {x}^{2} - 7 {x}^{2} + 5x \\ = x(4x - 7x + 5) \\ = x( 5 - 3x) \\ = { \underline{ \underline{ \: \: 5x - 3 {x}^{2} \: \: }}}$

7 0

3 years ago

Read 2 more answers

Find the discriminant, and determine the number of real solutions. then solve x^2 +8x+20=0

vodomira [7]

Answer:

Part 1) The quadratic equation has zero real solutions

Part 2) The solutions are

$x_1=-4+2i$ and $x_2=-4-2i$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}+8x+20=0$

$a=1\\b=8\\c=20$

The discriminant is equal to

$D=(b^{2}-4ac)$

If D=0 -----> the quadratic equation has only one real solution

If D>0 -----> the quadratic equation has two real solutions

If D<0 -----> the quadratic equation has two complex solutions

<em>Find the value of D</em>

$D=8^{2}-4(1)(20)=-16$ -----> the quadratic equation has two complex solutions

<em>Find out the solutions</em>

substitute the values of a,b and c in the formula

$x=\frac{-8(+/-)\sqrt{8^{2}-4(1)(20)}} {2(1)}$

$x=\frac{-8(+/-)\sqrt{-16}} {2}$

Remember that

$i=\sqrt{-1}$

$x=\frac{-8(+/-)4i} {2}$

$x_1=\frac{-8(+)4i} {2}=-4+2i$

$x_2=\frac{-8(-)4i} {2}=-4-2i$

8 0

3 years ago

Count the number of strings of length 9 over the alphabet {a, b, c} subject to each of the following restrictions.

Andrew [12]

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document. I hope my explanation will help you in understanding this particular question.

Step-by-step explanation: