The equation is in the format
where a is the initial value (when t=0), b is the rate of change between terms, and t is the amount of time.
Our initial value is 100. We find the rate of change by first finding the percent of change:
amount of change/original amount
= 20/100 = 0.2
This is a percent decrease, so we will subtract it from 1:
1-0.2 = 0.8
This goes in for b.
Answer to part A: 11w^2+7z^2
Answer to part B: 14w^2+9w
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Explanation:
For part A, the expression 4w^2+7w^2+7z^2 has one pair of like terms. That pair is 4w^2 and 7w^2 which combine to 11w^2. You add the coefficients to get 4+7 = 11, then tack w^2 onto everything to say 4w^2+7w^2 = 11w^2
We cannot combine 11w^2 and 7z^2 as they aren't like terms. So we leave it as 11w^2+7z^2
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In part B, the like terms are 15w and -9w. They combine to 15w-9w = 6w. You can think of it like 15-9 = 6 then stick a 'w' to each term. We cannot combine the w^2 term with the w terms.
There are four quantum numbers: n, l, ml and ms. When the orbital is 4d, the 4 is corresponding to n. Thus, n=4. Then, the d corresponds to l = 2. Now, to find the value for ml, take the values of -l to +l. Therefore,
<em>ml = -2, -1, 0, 1, 2</em>
<em>Then,ms could only be either +1 or -1.</em>
Answer is
tan º = 16/x
16/tan 33=x
x=24.637
It’s 4(25+3) because you need to put a line over the 25 and 3 so the 4 can multiply it like so