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3 years ago

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Suppose an architect draws a segment on a scale drawing with the end points (0,0) and (3⁄4,9⁄10). The same segment on the actual

structure has the end points (0,0) and (30,36). What proportion could model this situation?

1 answer:

Kipish [7]3 years ago

6 0

Segment drawn on scale having end points O (0,0) and A $(\frac{3}{4},\frac{9}{10})$ is a line segment.

O A= $\sqrt{[\frac{3}{4} -0]^{2} +[\frac{9}{10} -0]^{2}\\\\$

O A = $= \sqrt{\frac{9}{16}+\frac{81}{100}$

= $\sqrt\frac{549}{400}$

= $\frac{\sqrt{549}}{20}$

Now , the same segment actual structure having end points O'(0,0) and B (30,36) is also a line segment.

O'B= $\sqrt{(30-0)^{2}+(36-0)^{2}$

= $\sqrt{900+1296}$

= $\sqrt {2196}$

= 2√549

$\frac{\text{Actual length}}{\text{Length on scale}}=\frac{OB'}{OA}=\frac{2\sqrt549}{\frac{\sqrt549}{20}}=40$ [Cancelling √549 from numerator and denominator]

So, Actual length = 40 × Length on scale

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On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant

VladimirAG [237]

Answer:

a) $2\frac{7}{12}$ kg of plant food did Sheldon have left.

b) She need is $\frac{43}{12}$ kg and she don't have enough to left.

Step-by-step explanation:

Given : On Sunday, Sheldon bought $4\frac{1}{2}$ kg of plant food. He used $1\frac{2}{3}$ kg on his strawberry plants and used $\frac{1}{4}$ kg for his tomato plants.

To find :

a) How many kilograms of plant food did Sheldon have left? Write one or more equations to show how you reached your answer.

Solution :

Sheldon bought plant food $4\frac{1}{2}=\frac{9}{2}$ kg.

He used strawberry plants $1\frac{2}{3}=\frac{5}{3}$ kg.

He used tomato plants $\frac{1}{4}$ kg

Kilograms of plant food did Sheldon have left is given by,

$L=\frac{9}{2}-(\frac{5}{3}+\frac{1}{4})$

$L=\frac{9}{2}-\frac{23}{12}$

$L=\frac{54-23}{12}$

$L=\frac{31}{12}$

$L=2\frac{7}{12}$

Therefore, $2\frac{7}{12}$ kg of plant food did Sheldon have left.

b) Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will he need? Does he have enough left to do so?

Solution :

Sheldon wants to feed his strawberry plants 2 more times.

i.e. Strawberry plants used is $2(\frac{5}{3})=\frac{10}{3}$ kg.

His tomato plants one more time i.e. $\frac{1}{4}$ kg.

Total plant she need is $\frac{10}{3}+\frac{1}{4}=\frac{43}{12}$

As $\frac{31}{12}$

No she don't have enough to left.

4 0

3 years ago

One serving of granola provides 4% of the protein you need daily. You must get the remaining 48 grams from other sources. How ma

Anna35 [415]

You will need 46.08 grams.

48 • 0.04 (4%) = 1.92
multiply 48 by 0.04 to find what 4% of 48g is
48 - 1.92 = 46.08
then subtract the 4% to get the rest amount

6 0

3 years ago

Find the value of each variable in the parallelogram

wlad13 [49]

Answer:

B= 90

C= 80

D= 100

Step-by-step explanation:

So let’s start with the bottom angles.

We know that the adjacent angles in a parallelogram add up to 180° so our equation would be $(b-10) + (b+10)=180$ . So let’s simplify it b and b are both the same variables so we will get 2b and -10 + 10 is 0 so we get the following equation $2b=180$ .

So now we divide 180 and 2 and we get 90 as b.

So one side will be 100 because of the +10 and the other 90 because of the -10.

Now for the next side.

$d+c=180$

So we know that b+10 is adjacent to c so 180-100 is 80, so 80 is c.

Now for d.

b-10 is 80 so 180-80 is 100, so d is 100.

7 0

3 years ago

20 points for correct answer and a brainliest for first correct answer!

natka813 [3]

Answer:

D

Step-by-step explanation:

6 0

3 years ago

A cylinder has a volume of 360 cubic centimeters. Find the volume of a cone with the same height and diameter as

harina [27]

Formula for the cylinder = V=πr2h

Formula for the cone = 1/3πr²H

Description:

So if the cone and a cylinder have the same radius and the same height then it will be greater. So plug in these formula.

Formula:

Vcone = 3Vcone

Vcylinder = 360cm³

Vcone = 1/3 360cm³ = 120cm³

Answer: 120cm³

Hope this helps.

4 0

3 years ago