A garden snail moves 1/6 foot in 1/hour. find the speed of the snail in feet per hour

Help, I'm doing rhis problem and need help checking if I'm right.

umka2103 [35]

To me it looks like your right

7 0

3 years ago

A ladder is leaning up against a house. The ladder is 20 feet long and the base of the ladder is 12 feet away from the house. Ho

MrRa [10]

Answer:

16 feet

Step-by-step explanation:

The length of the ladder=20 feet

Distance from the base of the ladder to the house = 12 feet

You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.

To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.

From Pythagoras theorem

$Hyp^2=Opp^2+Adj^2\\20^2=12^2+Adj^2\\Adj^2=400-144\\Adj^2=256\\Adj=\sqrt{256}=16$

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.

8 0

3 years ago

Read 2 more answers

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

Alisiya [41]

The answer is 2(–4y + 13) – 3y = –29

Step 1: Express x from the second equation
Step 2: Substitute x into the first equation:

The system of equations is:
2x – 3y = –29
x + 4y = 13

Step 1:
The second equation is: x + 4y = 13
Rearrange it to get x: x = - 4y + 13

Step 2:
The first equation is: 2x – 3y = –29
The second equation is: x = - 4y + 13
Substitute x from the second equation into the first one:
2(-4y + 13) - 3y = -29

Therefore, the second choice is correct.

5 0

4 years ago

Omar wants to purchase a bike helmet for 22.55 and a bike for 134.45.

noname [10]

Answer:

$169.96 dollars

Step-by-step explanation:

Given the following questions:

8.25% of 22.55 and 134.45

In order to find the answer, we will have to add the initial costs of the items together, then we will calculate using the formula for percentages to find the tax rate.

$22.55+134.45=157$
$157$

Calculate the percentage:
 $\frac{p\times c}{100}$
$\frac{8.25\times157}{100} =8.25\times157=1295.25\div100=12.9525$
$=12.9525$
$12.9525$
$2 < 5$
$=12.96$

Add the sales tax:
$157+12.96=169.96$
$=169.96$

Which means the two items along with an 8.25% sales tax costs "$169.96 dollars."

Hope this helps.

5 0

2 years ago

One stats class consists of 52 women and 28 men. Assume the average exam score on Exam 1 was 74 (σ = 10.43; assume the whole cla

Svetllana [295]

Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

6 0

3 years ago