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3 years ago

Marcelino bought balloons to sell at lunches to raise money for charity

Mathematics

2 answers:

Arada [10]3 years ago

4 0

Answer:

Marcelino will have $7.50: his costs are more than his profits.

Step-by-step explanation:

22.50 + 7.50 + 15.00

In total Marcelino spent $45 to make these balloons.

He wants to sell each balloon for $1.25.

If he sells the 30 balloons he bought for $1.25 he will make:

30 * 1.25 = $37.50... okay he made some money, BUT he spent $45 dollars for the items.

45 - 37.50 = $7.50, Marcelino made no profit... he still needs to make $7.50 to pay off his own costs.

GaryK [48]3 years ago

3 0

Answer:

Step-by-step explanation:

Its c on my computer

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Evaluate (2 - 5i)(p + q)i when p = 2 and q = 5i a. 29i b. 291-20 C.-21i d.29

attashe74 [19]

Answer:

A. 29i

Step-by-step explanation:

Step 1: Plug in given variables

(2 - 5i)(2 + 5i)i

Step 2: Difference of squares (expand)

(4 - 25i²)i

Step 3: Imaginary numbers rules

(4 - 25(-1))i

Step 4: Combine like terms

(4 + 25)i

(29)i

Your final answer will be 29i

8 0

3 years ago

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What is the length of pr ? PLEASE HELP

Karolina [17]

The angles in the triangles are the same, so you know the triangles are similar. Sides PQ and AB correspond as do sides PR and AC. Because the triangles are similar, you know that
PR/AC = PQ/AB
PR/24 = 5/20
Multiplying this equation by 24 gives
PR = 24*(5/20) = 6

The appropriate choice is ...
C. 6

3 0

3 years ago

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3√6-4√6 Please simplify

Eva8 [605]

Answer:

= -√6

Step-by-step explanation:

1) collect like terms by subtracting coefficients:

3√6 - 4√6

(3-4)√6

2) calculate (3-4):

(3-4)√6

-1√6

3) the coefficient of -1 does not have to be written, but the negative sign remains:

-1√6

-√6

so therefore:

-√6 is your answer

3 0

3 years ago

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

$(10)^2=(8)^2+(6)^2$

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

$(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2$

$(25+1)^2=(25-1)^2+(10)^2$

$(26)^2=(24)^2+(10)^2$

So (10,24,26) is another.

Let (x,y)=(5,2).

$(5^2+2^2)^2=(5^2-2^2)^2+(2\cdot5\cdot2)^2$

$(25+4)^2=(25-4)^2+(20)^2$

$(29)^2=(21)^2+(20)^2$

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

$(5^2+3^2)^2=(5^2-3^2)^2+(2\cdot5\cdot3)^2$

$(25+9)^2=(25-9)^2+(30)^2$

$(34)^2=(16)^2+(30)^2$

Another Pythagorean Triple is (16,30,34).

Let (x,y)=(5,4)

$(5^2+4^2)^2=(5^2-4^2)^2+(2\cdot5\cdot4)^2$

$(25+16)^2=(25-16)^2+(40)^2$

$(41)^2=(9)^2+(40)^2$

Another is (9,40,41).

5 0

3 years ago

Marco's mom has measured his height in centimeters every few months between the ages of 4.5 and 7.5. The recorded values are bes

Contact [7]

Answer:

Extrapolation

Step-by-step explanation:

Extrapolation is a type of estimation, beyond the original observation range. In this case, the observation range is from 4.5 to 7.5 years. Marco's mom is extrapolating the regression line to estimate Marco's height at 14 years old. This sort of estimation assumes that Marco's height will continue changing at the same rate until he is 14 years old.

7 0

3 years ago