Ask question

Ask question

All categories

3 years ago

14

Mrs mccarthy has 2 separate 7 foot boards she needs 11 inches long how many will she have if she has 2 boards

1 answer:

Trava [24]3 years ago

6 0

2 separate 7 ft boards = (2 * 7) = 14 feet
1 ft = 12 inches....so 14 feet = (14 * 12) = 168 inches
168/11 = 15.27 <== she has 15 eleven inch boards.

You might be interested in

The table above shows a number of each type of item in Harry’s liquor what’s the ratio of paper clips to the total number of ite

SVETLANKA909090 [29]

Answer:

its 3:5

Step-by-step explanation: if you don't see the answer talk with your teacher because I did it and I got 3:5

6 0

3 years ago

Need help with number 4 and number 5

ivanzaharov [21]

Answer:

4. D

5. A

Step-by-step explanation:

For #4, I first divided 15 by 4 and saw what the greatest whole number it was divisiable by. Then I wrote the remain as a fraction

For #5, I first multiplied by 4*6 and then add 5 to that answer

7 0

3 years ago

Need help! it’s due today. Brainliest to whoever gets correct

chubhunter [2.5K]

Answer:

B. about 41

A. 11

Step-by-B.step explanation:

6 0

3 years ago

Read 2 more answers

Tracy Tomillo is a disc jockey at WGMH. Her annual salary is $52,750. What is her monthly salary?

Juli2301 [7.4K]

Answer:

Her monthly salary is $4395.83

Step-by-step explanation:

Annual = 12 months

12 months = $52 750

1 month = $52 750 ÷ 12

= $4395.83(2d.p)

Monthly = $4395.83

(Correct me if i am wrong)

7 0

3 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago