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inn [45]
3 years ago
9

Convert 21 99 to a decimal using long division.

Mathematics
1 answer:
Elden [556K]3 years ago
3 0
What so u mean convert '20 99' in decimal . It's already in simplest form
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Maria is using a coordinate plane with the axes labeled only with integers. She says that the point (−0.5, 2) cannot be plotted
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Answer:

Integers ={Positive Natuaral Number +Natural numbers having negative sign behind it+Zero}

      ={------,-3,-2,-1,0,1,2,3,..........}

→Points marked on the X and Y axis on the Coordinate Plane=Integers only

→Point to be marked on the coordinate plane =(-0.5,2)

→As, points on both X and Y axis are integers only.To mark, -0.5 , mark a line between , 0 and -1,that will be ,-0.5.

→You can mark , any terminating decimal on the number line, which is marked with integers only.

→Terminating decimals are those decimals having 2^a ,\text{or}5^b, \text{or} 2^a \times 5^b in the denominator of a fraction.

So, to plot any terminating Decimal on the coordinate plane, you have to use property of Rational Numbers ,which is, you can find infinite number of terminating Decimal between two terminating Decimal.

→Mark -0.5 between 0 and -1 on the X axis.Similarly, mark integer 2 on the Y axis.Draw a line parallel to Y axis ,passing from (-0.5,0) and line parallel to X axis passing through (0,2).The intersection of these two lines will be required point (-0.5,2).

3 0
3 years ago
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Perform the indicated operation.<br><br> 4/11 · 10/8<br><br> 4/11<br> 5/11<br> 6/11
Dimas [21]
4/11 * 10/8

Multiplying fractions
1) multiply the numerators: 4 * 10 = 40
2) multiply the denominators: 11 * 8 = 88
3) simplify the fraction
40/88 ⇒ 10/22 ⇒ 5/11

40 ÷ 4 = 10
88 ÷ 4 = 22

10 ÷ 2 = 5
22 ÷ 2 = 11

4/11 * 10/8 = 5/11
7 0
3 years ago
Can anyone help me with my algebra 2 test ?
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Answer:

what do you need?

Step-by-step explanation:

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If you need to measure the width of your MP3 player to make sure it will fit in carrying case on sale at the mall, which of the
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Dekameter think 
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Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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