Quadrilateral ABCD has vertices at A(-2, -4), B(1, -1), C(-2, 2) and D(-5, -1). What is the name of the figure?
1 answer:
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Answer:
The functions given are:
f(x) = x²
g(x) = f(-4x-3) + 1
First, find f(-4x-3):
f(x) = x²
f(-4x-3) = (-4x-3)²
Find g(x):
g(x) = f(-4x-3) + 1
g(x) = (-4x-3)² + 1
g(x) = (-1)² (4x+3)² + 1
g(x) = (4x+3)² + 1
First take
y = (x)²
Compress the graph along x axis by multiplying x with 4
y = (4x)²
Shift the graph left by 0.75 units, by adding 3 to x term.
y = (4x+3)²
Shift the graph up by 1 unit by adding 1 to the total terms.
y = (4x+3)² +1
