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2 years ago

Quadrilateral ABCD has vertices at A(-2, -4), B(1, -1), C(-2, 2) and D(-5, -1). What is the name of the figure?

Mathematics

1 answer:

dimaraw [331]2 years ago

4 0

Answer:

a square

Step-by-step explanation:

bc if u plot them on a graph, you get a rhombus but when you turn the page, you also get a square. it said under the rhombus, not a square, so we cross that one out and we hv the res. all the sides are equal so the only answer left is a square

hope it helped xx

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2 years ago

What is the value of y? O A. Cannot be determined O B. 60 O C. 36 O D. 120 HELP!

Angelina_Jolie [31]

Answer: 60

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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2 years ago

Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.

Masja [62]

Answer:

See below.

Step-by-step explanation:

So, we have:

$\sec(\theta)=-2/\sqrt{3}$

Recall that secant is simply the reciprocal of cosine. So we can:

$\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2$

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.

Therefore, the possible values for theta is

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7π/6 + 2nπ

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2 years ago