Total liters of water needed = number of attendee x water consumption/attendee wherenumber of attendee = 7000 attendeewater consumption/attendee = 0.5litre of water/attendeetotal = 7000 x 0.5 litre = 3500 litrescomputing the water requirement per 200 litre containerwater requirement in the event = 3500 litres/200 litre /container = 17.5 containersThe water requirement in the event at the arena of 7000 attendees is 17.5 containers.
Answer:
x = 2
y = -3
Step-by-step explanation:
y = x - 5 -------------------(I)
x + y = -1 ----------------(II)
Substitute y = x -5 in equation (II)
x + (x - 5) = -1
x + x - 5 = -1 {Combine like terms}
2x - 5 = -1 {Add 5 to both sides}
2x = -1 + 5
2x = 4 {Divide both sides by 2}
x = 4/2
x = 2
Substitute x = 2 in equation (I)
y = 2 - 5
y = -3
Since, the population of a town increased from 5,400 to 6,000 people. We have to calculate the percent of increase.
Firstly, we will find the difference of 6000 and 5400,
6000-5400 = 600
Secondly, we will divide 600 by 5400,
So, 
= 0.1111
Thirdly, we will multiply 0.1111 by 100%
= 11.11 %
Therefore, there is 11.11% increase in the population of a town.
The right answer for the question that is being asked and shown above is that: "C.The distributions are somewhat similar." Data Set 1 has a mean of 120 and a MAD of 4. Data Set 2 has a mean of 132 and a MAD of 3.you conclude about the two distributions is that C.The distributions are somewhat similar.
