the large bag is 5/6 lb, the smaller bags will be 1/3 lb, so it should be 5/6 ÷ 1/3
![\bf \cfrac{5}{6}\div \cfrac{1}{3}\implies \cfrac{5}{\underset{2}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\implies \cfrac{5}{2}\implies 2\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B5%7D%7B6%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B%5Cunderset%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%206%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Ccdot%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%203%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Cimplies%202%5Cfrac%7B1%7D%7B2%7D)
Answer:
y=3x.........1
y=x^2-10.......2
substituting value of eq 1 to 2
3x=x^2-10
x^2-10-3x=0
x^2-3x-10=0
x^2-5x+2x-10=0
X(x-5)+2(x-5)=0
(x-5)(X+2)=0
then
X=5 or X=-2
again
y=??
when X=5
y=3×5=15
when X=-2
y=-6
We have the following data:
Margin of Error = E = 2.7 % = 0.027
Sample size = n = 900
Proportion of adults in favor = p = 60% = 0.6
We need to find the confidence level. For this first we need to find the z value.
The margin of error for a population proportion is given as:

Using the values, we get:
As, seen from the z table, z=1.65 corresponds to the confidence level 90%. So, the answer to this question is option B
( x^4 - 4 x³ + 2 x² - 4 x + 1 ) : ( x² + 1 ) = x² - 4 x + 1
- x^4 - x²
------------------------
- 4 x³ + x² - 4 x
4 x³ + 4 x
-----------------------
x² + 1
- x² - 1
----------------
R ( x ) = 0
( x^4 - 4 x³ + 2 x² - 4 x + 1) = ( x² + 1 ) ( x² - 4 x + 1 )
Answer:
B Survey a random sample of eighth-grade students
Step-by-step explanation:
In order to reach the best conclusion without biased data, the best sampling method would be B because not only does it survey 8th graders, but it also surveys a random group, ensuring that not all of the students are potentially excelling in and/or having trouble with homework.