PLEASE HELP ASAP

The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3

Vesna [10]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the center
r - the radius

The center is (4,0), the length of the radius is 2√3.
$(x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\
\boxed{(x-4)^2+y^2=12}$

8 0

3 years ago

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4x+5-2=3x+7x-15 I dont get how to get the answer for this please help.

fredd [130]

Hello there! How are you today?

4x + 5 -2 = 3x + 7x - 15

First, we need to get the variable (x) on one side. To do that, we must simplify the right side of the equation, and then decide what to do from there, so let's proceed to do so.

3x + 7x = 10x

4x + 5 - 2= 10x - 15

Now we have x simplified on both sides of the equation. However, we need x to be on one side of the equation in order to solve for it.
Subtract 4x from both sides.

4x - 4x = 0
10x - 4x = 6x

We are now left with:
6x - 15 = 5 - 2

Simplify the right side of the equation.

5 - 2 = 3

6x - 15 = 3

Now we need to isolate x. To isolate x, we need to add 15 to both sides, as x is being subtracted by 15, and adding 15 will cancel it out.

-15 + 15 = 0
3 + 15 = 18

We now are left with:
6x = 18

Now we only have one step left, and that is to solve for x. Since x is being multiplied by 6, we need to perform the opposite order of operations to cancel it out. To do that, we must divide both sides by 6 to solve for x.

6x = 18
Divide both sides by 6.

6x / 6 = x
18 / 6 = 3

We are now left with the solution:

x = 3

I hope this helps!

4 0

3 years ago

Marcos had 15 coins in nickels and quarters. He had 3 more quarters than nickels. He wrote a system of equations to represent th

hodyreva [135]

Answer:

There are 6 coins in nickels and 9 coins in quarters.

Step-by-step explanation:

Now, to find the solution.

According to question:

The number of nickels = $x$ .