"Of the gravy" lol
To find the x-intercepts, you make f(x) = 0 and solve for x by setting each factor equal to 0.
0 = x(x + 1)(x - 5)(x - 7)
x = 0
x + 1 = 0
x = - 1
x - 5 = 0
x = 5
x - 7 = 0
x = 7
Your x-intercepts are x = - 1, 0, 5, 7
OR
There are x-intercepts at (- 1, 0), (0, 0), (5, 0), and (7, 0).
Answer:
Step-by-step explanation:
c
It would be 6n because 2times 3 is 6 and bring down the n
x^2 = the first integer
(x - 1)^2 = the second integer.
x^2 - (x - 1)^2 = ?
First, let's plug a number into our equation for x.
(2)^2 - (2 - 1)^2 = ?
4 - (1)^2 = ?
4 - 1 = 3
As we can see the difference is odd but it's also the sum of the two consecutive integers.
2 + 1 = 3.
This works for all numbers. Let's plug another number into our equation for x.
(4)^2 - (4 - 1)^2 = ?
16 - (3)^2 = ?
16 - 9 = 7
4 + 3 = 7
Try any number and it will always be odd.
