The expected length of code for one encoded symbol is
where is the probability of picking the letter , and is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length , we would then expect .
By definition of variance, we have
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get .
Answer:
He should have to spell at least 36 of these words correctly.
Step-by-step explanation:
40 words.
He must spell at least 90% of those words correctly.
At least how many words should he have to spell correctly to get the prize?
90% of 40. So
0.9*40 = 4*9 = 36
He should have to spell at least 36 of these words correctly.
Answer:
add 11 and 7 togive you 18 and it is over 2.therefore the answer is 1/9
Answer:
i believe it is 497 after the 30% mark down
Step-by-step explanation:
i subtracted 30% from 710