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stepladder [879]
3 years ago
13

What does +79 - 21 =

Mathematics
1 answer:
valina [46]3 years ago
5 0
Lol the answer is 58
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Solve the following by elimination method <br> 11x+15y+23=0 and 7x-2y-20=0
mr Goodwill [35]
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)

Multiply equation (1) by 2:
22x + 30y + 46 = 0

Multiply equation (2) by 15:
105x - 30y - 300 = 0

Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]

Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3

Therefore, x = 2 and y = -3.
7 0
4 years ago
Inqualtites question<br><br>Complete the inequality expression that describes this set of numbers:
RideAnS [48]

Answer:

- 3 ≤ x < 0

Step-by-step explanation:

- 3 is included in the set thus x can equal - 3

- 3 is less than all other values in the set including the largest value of 0, thus

- 3 ≤ x < 0

3 0
3 years ago
In a cylindrical wooden block with a radius of 7 cm and a height of 14 cm, hemispherical blocks with
Sunny_sXe [5.5K]

9514 1404 393

Answer:

  1372π/3 cm^3 ≈ 1436.8 cm^3

Step-by-step explanation:

The diameter and height of the cylinder are both 14 cm. The resulting solid will be a 14 cm sphere. Its volume is ...

  V = 4/3πr^3 = 4/3π(7 cm)^3 = 1372π/3 cm^3 ≈ 1436.8 cm^3

4 0
3 years ago
FIND THE SUM:<br> (6x^2-2x-3)+(x^2-3x+1)<br><br> 1.6x^2+6x+3<br> 2.7x^2+5x+2<br> 3.7x^2-5x-2
Butoxors [25]

8x^2-5x-2

method

open bracket

6x^2-2x-3+x^2-3x+1

collect like terms

6x^2+2x^2-3-3x+1

8x^2-3-3x+1

again collect like terms

8x^2-2x-3x-3+1

8x^2-5x-3+1. (-×-=+ addition but keeping sign minus

8x-5x-2. (-×+=-)

5 0
3 years ago
BRAINLIEST TO CORRECT ANSWER!!! NO links as answers, or you will be reported!! (question 4)
In-s [12.5K]

Answer:

Hello! Your answer would be, C) Divide by 2

Step-by-step explanation:

And plz don't be mean. :(

Hope I helped! Brainiest plz!♥ Have a nice afternoon. Hope you make a 100%! -Amelia

8 0
3 years ago
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