Answer:
The answer to the question is;
The number of papers expected to be handed in before receiving each possible grade at least once is 14.93.
Step-by-step explanation:
To solve the question , we note that it is a geometric distribution question which have equal probabilities and therefore is a form of Binomial distribution with Bernoulli trials, where we are conducting the trials till we have r successes
Since we have r = 6, we will have to find the expected value of the number of trials till the nth paper handed in receives a previously awarded grade.
We therefore have,
The Probability that out of six papers turned 5 are different scores is given by
P(Y=5) = p'= q⁵p = (1-p)⁵p = 3125/46656
Therefore p' = the probability of receiving different grades once then the expected value is given by
E(X) = 1/p' = 46656/3125 = 14.93.
Answer:
A.
Step-by-step explanation:
m = y2-y1/x2-x1
m = 12-4/15-5
m = 8/10
m = 4/5
Answer:
figure 5
Step-by-step explanation:
Answer:
25%
Step-by-step explanation:
There are 4 spots and to get the same you would land on the same 1
Which would be 1/4=25%
Hope this helps!
7+ 3x= -8
-8-7=-15
-15 divided by 3= -5
-5 is the answer
