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babymother [125]
3 years ago
6

I WILL MARK YOU BRAINLIEST!!!!

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0
I’m pretty sure it’s option D
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Write an equation in standard form for the line, where the points (-2, -1) and (0, 4) are on the line
DedPeter [7]

Answer:

An equation in standard form for the line is:

\frac{5}{2}x-y=-4

Step-by-step explanation:

Given the points

  • (-2, -1) and (0, 4)

The slope between two points

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-2,\:-1\right),\:\left(x_2,\:y_2\right)=\left(0,\:4\right)

m=\frac{4-\left(-1\right)}{0-\left(-2\right)}

m=\frac{5}{2}

Writing the equation in point-slope form

As the point-slope form of the line equation is defined by

y-y_1=m\left(x-x_1\right)

Putting the point (-2, -1) and the slope m=1 in the line equation

y-\left(-1\right)=\frac{5}{2}\left(x-\left(-2\right)\right)

y+1=\frac{5}{2}\left(x+2\right)

y=\frac{5}{2}x+4

Writing the equation in the standard form form

As we know that the equation in the standard form is

Ax+By=C

where x and y are variables and A, B and C are constants

so

y=\frac{5}{2}x+4

\frac{5}{2}x-y=-4

Therefore, an equation in standard form for the line is:

\frac{5}{2}x-y=-4

7 0
3 years ago
What is the length of the diagonal of the triangle?
Setler79 [48]

Answer:

21.25

Step-by-step explanation:

use the Pythagorean theorem, it is given that the shape is a rectangle so all opposite sides are congruent and all angles are right, since we know that the diagonal forms a right triangle we can use the pythagorean theorem

the Pythagorean theorm is a^2+b^2=c^2 where a and b are the legs (in this case the side of the triangle) and c is the hypotenuse which is the longest side in a right triangle

17^2+12.75^2=x^2

x^2=7225/16

now take the square root of both sides and you get -21.25 and 21.25

distance CAN NOT be negative so -21.25 isn't an option

7 0
4 years ago
The slope of the tangent line to the curve x^3y+y^2-x^2=5 at the point (2,1) is
zheka24 [161]

Answer:

-4/5

Step-by-step explanation:

To find the slope of the tangent to the equation at any point we must differentiate the equation.

x^3y+y^2-x^2=5

3x^2y+x^3y'+2yy'-2x=0

Gather terms with y' on one side and terms without on opposing side.

x^3y'+2yy'=2x-3x^2y

Factor left side

y'(x^3+2y)=2x-3x^2y

Divide both sides by (x^3+2y)

y'=(2x-3x^2y)/(x^3+2y)

y' is the slope any tangent to the given equation at point (x,y).

Plug in (2,1):

y'=(2(2)-3(2)^2(1))/((2)^3+2(1))

Simplify:

y'=(4-12)/(8+2)

y'=-8/10

y'=-4/5

5 0
3 years ago
Martin took a total of 20 quizzes over the course of 5 weeks. After attending 15 weeks of school this quarter, how many quizzes
kirza4 [7]

Answer:

60

Step-by-step explanation:

First we divide 5 from 20 then we get 4 so 4 x 15 would be 60.

4 0
3 years ago
The upper quartile of a set of data is the mode of the upper half of the data. <br> True<br> False
Arturiano [62]
I think it might be false, I could be wrong though. 
Hopefully that helped! :) 
7 0
3 years ago
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