Let X be a discrete random variable with geometric distribution.
Let x be the number of tests and p the probability of success in each trial, then the probability distribution is:
P (X = x) = p * (1-p) ^ (x-1). With x = (1, 2, 3 ... n).
This function measures the probability P of obtaining the first success at the x attempt.
We need to know the probability of obtaining the first success at the third trial.
Where a success is defined as a customer buying online.
The probability of success in each trial is p = 0.3.
So:
P (X = 3) = 0.3 * (1-0.3) ^ (3-1)
P (X = 3) = 0.147
The probability of obtaining the first success at the third trial is 14.7%
Do the following:
$8.40-$7.15=$1.25
Then divide 1.25 by the difference of tickets which is 3
1.25/3=0.42 (that's rounded to nearest cent)
Not sure of the question...1 missing vs 8 found
or 1 missing vs 9 piece puzzle
We want to know how many 1/8's are in 3/4, so we divide.
Flip the 2nd fraction and multiply:
Multiply the numerators and denominators together:
Divide:
