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fomenos
3 years ago
12

A ball is kicked into the air and follows the path described by h(t)= – 4.9t^2 + 6t + 0.6, where t is the time in seconds and h

is the height in meters above the ground. Find the maximum height of the ball. What value would you have to change in the equation if the maximum height of the ball is more than 2.4 meters?
Mathematics
1 answer:
miv72 [106K]3 years ago
5 0
The maximum value can be determined by taking the derivative of the function.

(dh/dt) [h(t)] = h'(x) = -9.8t + 6

Set h'(x) = 0 to find the critical point

-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8

Plug the time back into the function to find the height.

h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4

And I don't understand your second question.
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Read 2 more answers
The central limit theorem states that sampling distributions are always the same shape as the population distribution from whenc
sergejj [24]

Explanation:

The sample mean is not always equal to the population mean but if we take more and more number of samples from the population then the mean of the sample would become equal to the population mean.

The Central Limit Theorem states that we can have a normal distribution of sample means even if the original population doesn't follow normal distribution, But we have to take a lot of samples.

Suppose a population doesn't follow normal distribution and is very skewed then we can still have sampling distribution that is completely normal if we take a lot of samples.

3 0
2 years ago
Write the equation of a line perpendicular to y=-12x+2 going through (0,-1)
DanielleElmas [232]

             \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

          <em>Write the equation of a line perpendicular to y=-12x+2 going </em>

<em>            through (0, -1)</em>

<em />

<em>      </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

        First, let's take a look at our provided information:-

  • A line \text{y=-12x+2}
  • A point (0, -1)
  • The line \text{y=-12x+2} is perpendicular to the line that goes through (0, -1)

     If two lines are perpendicular to each other, their slopes are opposite reciprocals of each other.

   So we take the slope of the given line, which is -12, change its sign from minus to plus:-

\Large\textit{12}

And now, We flip the number over:-

\Large\text{$\displaystyle\frac{1}{12}$}

Now that we've found the slope of the line, let's find its equation.

     The first step is to write it in point-slope form as follows:-

\longmapsto\sf{y-y_1=m(x-x_1)}

Replace letters with numbers,

\longmapsto\sf{y-(-1)=\displaystyle\frac{1}{12}(x-0)}

On simplification,

\longmapsto\sf{y+1=\displaystyle\frac{1}{12} (x-0)}

On further simplification,

\longmapsto\sf{y+1=\displaystyle\frac{1}{12} x}

Subtracting 1 on both sides,

\longmapsto\sf{y=\displaystyle\frac{1}{12} x-1}

\Uparrow\texttt{Our equation in slope-intercept form}

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

5 0
1 year ago
Solve 3(x+1) -2x= -6
s2008m [1.1K]
3(x + 1) - 2x = -6    |use distributive property: a(b + c) = ab + ac

3x + 3 - 2x = -6

x + 3 = -6    |subtract 3 from both sides

x = -9
6 0
3 years ago
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