what's the question? you only put a formula
r/3 + t = w to get r by itself (Which I think is your question)
r/3 + t = w subtract t from both sides
r/3 = w - t and times by 3 on both sides
r = 3(w-t)
Step-by-step explanation:
a. y = 2 + 4.3(-6)
y= 2- 25.8
y= -23.8 or y= -24
b. y= (9-3)2
18-6=12
c. y= 3.5-2
y= 1.5
d. y= 5(-2) - 4
y= -10-4
y= -14
Answer:
\frac{x^4+5}{x^3(x^2+6)} =\frac{A}{x}+\frac{B}{x^2}+\frac{D}{x^3} +\frac{Ex+F}{x^2+6}
Step-by-step explanation:

