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Nezavi [6.7K]
3 years ago
15

What is the product of 3a + 5 and 2a2 + 4a – 2?

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0

Answer:

all work is pictured and shown

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Stacy wants to build a patio with a small, circular pond in her backyard.The pond will have a 6-foot radius. She also wants to i
solong [7]
First we are going to find the Area of the pond using the area of a circle formula: A= \pi r^2
where
A is the area of the circle 
r is the radius of the circle 
We know for our problem that the pond will have a 6-foot radius, so r=6. Lets replace that value on our area formula:
A= \pi r^2
A= \pi (6)^2
A=113.1ft^{2}
We know that the <span>cost of installing the pond is $0.62 per square foot, so lets multiply the area we just found by the cost:
Total cost of pund=</span>(0.62)(113.1)=70.12 dollars

Now, let x be the width the rectangle, so its length will be x+13. Remember that the area of a rectangle is width times length, so:
A=x(x+13)
A=(x^2+13x)ft^2
Since the cost of installing ties is $1, the cost of installing ties in our rectangle will be x^2+13x dollars.

<span>Stacy can spend no more than $536 on this project, so we can setup an inequality relating the cost of the pound and the cost of installing ties:
</span>70.12+x^2+13x \leq 536
x^2+13x \leq 465.88

We can conclude that the inequality that can be used to fin the width, x, of the patio is x^2+13x \leq 465.88
6 0
3 years ago
Larry sold twice as many magazines as Jan. Henry sold 8 more magazines than Jan did. Larry and Henry sold the same amount of mag
Pavlova-9 [17]

Answer:

16 magazines jan sold

6 0
3 years ago
Read 2 more answers
Evaluate f(x)=x^2+1 for f(10)
marshall27 [118]
For f(10) replace x with 10 then solve:
f10) = 10^2 + 1
= 100 +1
= 101
4 0
3 years ago
The fith term of a G.P is 8 times the 2nd term find its common ratio​
Dovator [93]

Answer:

Common ratio r = 2

Step-by-step explanation:

\because the fith term of a G.P is 8 times the 2nd term.

\therefore  \: t_5 = 8\times t_2 \\ \therefore  \: ar^{5-1}=8\times \: ar^{2-1}  \\ \therefore  \: r^{4}=8\times \: r^{1} \\ \therefore  \: r^{3}=8 \\ \therefore  \:r^{3}= {2}^{3}  \\   \hspace{20 pt}\huge \red{ \boxed{\therefore  \:r= {2}}} \\

Hence, common ratio is 2.

6 0
3 years ago
Read 2 more answers
The segment that connects points (-2,8) and (3,-4) forms the diagonal of a rectangle. What are the lengths of the sides and diag
Rasek [7]

Answer:the lengths of the sides of the rectangle are 5 units and 12 units the length of the diagonal of the rectangle is 13 units

Step-by-step explanation:

4 0
3 years ago
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