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Minchanka [31]
3 years ago
8

Ned took a test with 25 questions. He lost 4 points for each of the 6 questions he got wrong and earned an additional 10 points

for answering a bonus question correctly. How many points do Ned receive overall?
Mathematics
2 answers:
lys-0071 [83]3 years ago
6 0
Ned got an overall grade of 86 percent because if each question is 4 points, then 6×4=24 but if he got a bonus 10 points, then you can do 24-10=14 and then you do 100-14 which equals your answer: 86.
Karo-lina-s [1.5K]3 years ago
6 0
-6 × 4 = -24
-24 + 10 = -14
100 - 14 = 86 points
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Use the method of cylindrical shells to find the volume v generated by rotating the region bounded by the curves about the given
kondor19780726 [428]

Answer:

The volume is \frac{16\pi}{e}

Step-by-step explanation:

* Lets talk about the shell method

- The shell method is to finding the volume by decomposing

 a solid of revolution into cylindrical shells

- Consider a region in the plane that is divided into thin vertical  

 rectangle

- If each vertical rectangle is revolved about the y-axis, we

 obtain a cylindrical shell, with the top and bottom removed.  

- The resulting volume of the cylindrical shell is the surface area 

  of the cylinder times the thickness of the cylinder

- The formula for the volume will be: V=\int\limits^b_a {2\pi xf(x)} \, dx

  where 2πx · f(x) is the surface area of the cylinder shell and  dx is its

  thickness

* Lets solve the problem

- To find the volume V generated by rotating the region bounded

  by the curves y = 4e^x and y = 4e^-x about the y-axis by use

  cylindrical shells

- Consider that the height of the cylinder is y = (4e^x - 4e^-x)

- Consider that the radius of the cylinder is x

- The limits are x = 0 and x = 1

- Lets take 2π and 4 as a common factor out the integration

∴ V=\int\limits^1_0 {2\pi x(4e^{x}-4e^{-x})} \, dx

∴ V=2\pi(4)\int\limits^1_0 ({xe^{x}-xe^{-x})} \, dx

- To integrate xe^{x} and xe^{-x} we will use

  integration by parts methods \int\ {uv'=uv-\int{v}\,u' }\,

∵ u = x

∴ u' = du/dx = 1 ⇒ differentiation x with respect to x is 1

∵ v' = dv/dx = e^x

- The integration e^x is e^x ÷ differentiation of x (1)

∴ v=\int\ {e^{x}}\, dx= e^{x}

∴ \int\ {xe^{x}} \, dx=xe^{x}-\int\ e^{x}\, dx=xe^{x}-e^{x}

- Similar we will integrate xe^-x

∵ u = x

∴ u' = du/dx = 1

∵ v' = dv/dx = e^-x

- The integration e^-x is e^x ÷ differentiation of -x (-1)

∴ v=\int\ {e^{-x}} \, dx=-e^{-x}

∴ \int\ {x}e^{-x}\, dx=-xe^{-x}+\int\ {e^{-x}} \, dx=-xe^{-x}-e^{-x}

∴ V = 8\pi \int\limits^1_0 ({xe^{x}-xe^{-x})} \, dx=8\pi[xe^{x}-e^{x}+xe^{-x}+e^{-x}] from 0 to 1

- Lets substitute x = 1 minus x = 0

∴ V=8\pi[(1)(e^{1})-(e^{1})+(1)(e^{-1})+(e^{-1})-(0)(e^{0})+(e^{0})-(0)(e^{0})-(e^{0})]

∴ V=8\pi[e^{1}-e^{1}+e^{-1}+e^{-1}-0+1-0-1]=8\pi[2e^{-1}]=16\pi e^{-1}

∵ e^{-1}=\frac{1}{e}

∴ V=\frac{16\pi}{e}

3 0
4 years ago
The equation shown below involves a perfect square trinomial. 4x2 + 20x + 25 = 7 Which of the following is a step in solving thi
fomenos
4 x^2 + 20 x + 25 = 7
Divide both sides by 4:
x^2 + 5 x + 25/4 = 7/4
Write the left-hand side as a square:
(x + 5/2)^2 = 7/4
Take the square root of both sides:
x + 5/2 = sqrt(7)/2 or x + 5/2 = -sqrt(7)/2
Subtract 5/2 from both sides:
x = sqrt(7)/2 - 5/2 or x + 5/2 = -sqrt(7)/2
Subtract 5/2 from both sides:
Answer:  x = sqrt(7)/2 - 5/2 or x = -5/2 - sqrt(7)/2
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Answer:

Do you mean strandord or expanded form?

Step-by-step explanation:

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Answer:

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I think it is 446,220
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