Well do 24 - 13.
You should get 11.
N = 11.
Answer:
<h2>c > 21</h2>
Step-by-step explanation:
![-\dfrac{1}{3}c7\qquad\text{multiply both sides by 3}\\\\c>21](https://tex.z-dn.net/?f=-%5Cdfrac%7B1%7D%7B3%7Dc%3C-7%5Cqquad%5Ctext%7Bchange%20the%20signs%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B3%7Dc%3E7%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%203%7D%5C%5C%5C%5Cc%3E21)
96 ! If you get x on one side and the # on the other you get x=96
Answer:
![BE = 4\sqrt2](https://tex.z-dn.net/?f=BE%20%3D%204%5Csqrt2)
Step-by-step explanation:
Given
The attached square
Required
Find BE
First, we calculate BD (the diagonal) using Pythagoras theorem.
![BD^2 = BA^2 + AD^2](https://tex.z-dn.net/?f=BD%5E2%20%3D%20BA%5E2%20%2B%20AD%5E2)
Since the shape is a square, then
![BA = AD = 8](https://tex.z-dn.net/?f=BA%20%3D%20AD%20%3D%208)
So:
![BD^2 = 8^2 + 8^2](https://tex.z-dn.net/?f=BD%5E2%20%3D%208%5E2%20%2B%208%5E2)
![BD^2 = 2(8^2)](https://tex.z-dn.net/?f=BD%5E2%20%3D%202%288%5E2%29)
Take square roots
![BD = \sqrt{2(8^2)](https://tex.z-dn.net/?f=BD%20%3D%20%5Csqrt%7B2%288%5E2%29)
![BD = \sqrt{2} * 8](https://tex.z-dn.net/?f=BD%20%3D%20%5Csqrt%7B2%7D%20%2A%208)
![BD = 8\sqrt{2}](https://tex.z-dn.net/?f=BD%20%3D%208%5Csqrt%7B2%7D)
BE is half BD.
So:
![BE = \frac{1}{2} * BD](https://tex.z-dn.net/?f=BE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20BD)
![BE = \frac{1}{2} * 8\sqrt2](https://tex.z-dn.net/?f=BE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%208%5Csqrt2)
![BE = 4\sqrt2](https://tex.z-dn.net/?f=BE%20%3D%204%5Csqrt2)
It would then be 500m+1000 and the total paid aka the T would change