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3 years ago

Complete the proof of the polynomial identity. help please draw a line from the correct answer to the correct blank

Mathematics

1 answer:

maw [93]3 years ago

3 0

Answer:

$x^4 +2x^2y^2+y^4\\\\2x^4+2x^2y^2+2y^4\\2(x^4+x^2y^2+y^4)$

Step-by-step explanation:

The proof of the polynomial identity shows that the left side equals the right side. To find what comes next, simplify the left side using order of operations (PEMDAS) by doing the exponent first, combing like terms and then simplifying.

$(x^2+y^2)^2$ simplifies to

$x^4 +2x^2y^2+y^4\\\\2x^4+2x^2y^2+2y^4\\2(x^4+x^2y^2+y^4)$

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Which expression represents 5 more than one-third y

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*Five more*

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1/3y

D. 1/3y+5

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3 years ago

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For f(x)=2x+1 and g(x)=x^2-7 find (f•g)(x)

skad [1K]

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3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

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3 years ago

Ahmad and Ben have a total of 78 keychains.

Murljashka [212]

Sorry it was tru

2C=B

C-A=6 A=C-6

A+B+C=78

78=C-6+2C+C

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3 years ago

2) Which of the following is the complete factorization of 6x^2? A. 6⋅x⋅x B. 2⋅3⋅x ^2 C. 2⋅3⋅x⋅x

Elena-2011 [213]

Answer:

C. 2• 3 • x • x

Step-by-step explanation:

Not sure but that's what I would guess

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3 years ago

Complete the proof of the polynomial identity. *help please draw a line from the correct answer to the correct blank*

Complete the proof of the polynomial identity. help please draw a line from the correct answer to the correct blank