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scoundrel [369]
3 years ago
14

Of 48 orchestra members 30 are girls what ratio compares the number of boy to girls

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0
You just simplify it down until to the point where you can't and it should be 3:5
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116 ÷ 16 = 7.25 pounds
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Solve for x.<br> Help ASAP please!!!
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Answer:

The value of x is 4

Step-by-step explanation:

In a right triangle, if a segment is drawn from the right angle ⊥ to the hypotenuse like the given figure, then

∵ The length of one side of the right triangle = (x + 2)

∵ The length of the hypotenuse = x + 5

∴ (x + 2)² = x (x + 5)

∵ (x + 2)² = (x + 2)(x + 2)

∴ (x + 2)(x + 2) = x(x + 5)

→ Simplify the two sides

∵ (x)(x) + (x)(2) + (2)(x) + (2)(2) = (x)(x) + (x)(5)

∴ x² + 2x + 2x + 4 = x² + 5x

→ Add the like terms in the left side

∴ x² + 4x + 4 = x² + 5x

→ Subtract x² from both sides

∵ x² - x² + 4x + 4 = x² - x² + 5x

∴ 4x + 4 = 5x

→ Subtract 4x from both sides

∴ 4x - 4x + 4 = 5x - 4x

∴ 4 = x

∴ The value of x is 4

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2 years ago
HELP!
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A)
8^2+9^2=c^264+81=c^2
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B)
Pythagerean Theorum: 
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3 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

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mihalych1998 [28]

Answer:

Step-by-step explanation:

1/3 as a decimal is 0.3333333 repeating

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