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Phantasy [73]
2 years ago
9

Freeee pointsssssssss​

Mathematics
2 answers:
aliina [53]2 years ago
7 0

Answer:

Thank you have a nice day:)

sammy [17]2 years ago
3 0
Thank you for the points:)
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At a fundraiser, students sold chocolate bars with almonds and chocolate bars with walnuts. The number of chocolate bars with al
BabaBlast [244]

Answer:

Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

Step-by-step explanation:

Let number chocolate bars with almonds be x

Also let number chocolate bars with walnuts be y

Given:

Number of chocolate bars with almonds that were sold one weekend was 3 less than 2 times the number of chocolate bars with walnuts.

Framing the above sentence in equation form we get;

x=2y -3

Also given:

The number of chocolate bars with walnuts plus 4 times the number of chocolate bars with almonds was 300.

Framing the above sentence in equation form we get;

4x+y=300

Now Substituting the value of x in above equation we get;

4x+y=300\\4(2y-3)+y=300\\8y-12+y=300\\9y=300+12\\9y=312\\\\y=\frac{312}{9} \approx 34.67

Now we will substitute the value of y in equation x=2y -3 we get;

x=2y-3 = 2\times34.67 -3 = 69.34-3\approx66.34

Hence, Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

6 0
3 years ago
Angela wrote the number 186,425 on the board in which number is the value of the digit six exactly 10 times the value of the dig
Butoxors [25]

So what’s the question? What are we trying to find?

4 0
3 years ago
In quadratic drag problem, the deceleration is proportional to the square of velocity
Mars2501 [29]
Part A

Given that a= \frac{dv}{dt} =-kv^2

Then, 

\int dv= -kv^2\int dt \\  \\ \Rightarrow v(t)=-kv^2t+c

For v(0)=v_0, then

v(0)=-kv^2(0)+c=v_0 \\  \\ \Rightarrow c=v_0

Thus, v(t)=-kv(t)^2t+v_0

For v(t)= \frac{1}{2} v_0, we have

\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\  \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\  \\ \Rightarrow kv_0t=2 \\  \\ \Rightarrow t= \frac{2}{kv_0}


Part B

Recall that from part A, 

v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\  \\ \Rightarrow dx=-kv^2tdt+v_0dt \\  \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\  \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a

Now, at initial position, t = 0 and v=v_0, thus we have

x=a

and when the velocity drops to half its value, v= \frac{1}{2} v_0 and t= \frac{2}{kv_0}

Thus,

x=- \frac{1}{2} k\left( \frac{1}{2} v_0\right)^2\left( \frac{2}{kv_0} \right)^2+v_0\left( \frac{2}{kv_0} \right)+a \\  \\ =- \frac{1}{2k} + \frac{2}{k} +a

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by

- \frac{1}{2k} + \frac{2}{k} +a-a \\  \\ = \frac{2}{k} - \frac{1}{2k} = \frac{3}{2k}
7 0
3 years ago
Which point lies on the line with point-slope equation y - 3 = 4(x + 7)?
Oksanka [162]

Answer:

D.

(-7, 3)

Step-by-step explanation:

Given equation

y - 3 = 4(x + 7)

points are in form of (x,y) that is first value represent value of coordinate and

second value y represents value of y coordinates.

to find which point lies on given line equation we need to substitute value of x and see if value of y obtained is same as given in the option or not.

______________________________________

A.

(7, 3)

substituting x with 7 in the equation

y - 3 = 4(7 + 7)

=> y - 3 = 4(14)

=> y - 3 = 56

=> y = 56+3 = 59

Thus, we see value of y when x is 7 is 59

which is not equal to 3 as given in option A hence option A is not correct choice

B.

(7, -3)

As seen above for x = 7 , y is 59 hence option B is also incorrect

C.

(-7, -3)

substituting x with -7 in the equation

y - 3 = 4(-7 + 7)

=> y - 3 = 4(0)

=> y - 3 = 0

=> y = 0+3 = 3

Thus, we see value of y when x is -7 is 3

which is not equal to -3 as given in option C hence option C is not correct choice

D.

(-7, 3)

As calculated above value of y when x is -7 is 3

hence

option D is correct choice.

8 0
3 years ago
What is an equation for the linear function whose graph contains the points (2, 5) and (3, 0) ?
S_A_V [24]
Y = -5x + 15

You can use point slope formula to get the answer
5 0
3 years ago
Read 2 more answers
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