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3 years ago

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a rectangle measures 3 yards by 4 feet what is the perimeter of the rectangle in inches show your work please

1 answer:

marissa [1.9K]3 years ago

7 0

Length: 3 yds. 36 in= 1 yd; 108 in.=3 yds
Width: 4 ft. 12 in=1 ft.; 48 in= 4 ft.
Sinve there are two lengths and widths in a rectangle, I like to multiply them both by 2 and add up the results. You also get the same answer when you add everything up twice. My answer is 312 in.

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Cloud [144]

Answer:

Step-by-step explanation:

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3 years ago

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Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z

Oliga [24]

<u>Part a)</u>

Given the expression

$54m^3n\:+\:81m^4n^2$

Apply exponent rule: $a^{b+c}=a^ba^c$

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn$ ∵ $m^4n^2=m^3mnn$

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

$=2\cdot \:27m^3n+3\cdot \:27m^3mnn$

Factor out the common term: 27m³n

$=27m^3n\left(2+3mn\right)$

Therefore,

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)$

<u>Part B)</u>

Given the expression

$15x^2y^3z+25x^3y^2z+35x^2y^2z$

Apply exponent rule: $a^{b+c}=a^ba^c$

$15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z$

Rewrite as

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Factor out common term 5y²x²z

$=5y^2x^2z\left(3y+5x+7\right)$

Therefore,

$15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)$

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3 years ago

7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and

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Answer:

A) JK and AB =

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B) AABC

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C) AABM:

$[tex] e \fbox{: }$ The value of k for which $\sin(jm) = \cos(x)$ is $\dfrac{\p}{2}$ ans[/tex]

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3 years ago

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Evgesh-ka [11]

Step-by-step explanation:

GIVEN

HERE

= 6+9+2+6+600÷30 { firstly add numbers }

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2 years ago

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lidiya [134]

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