Answer:
quadrant 3
negative negative is quadrant 3
Positive negative is quadrant 4
negative positive is 2
Positive positive is 1
Answer:
the object is in the air on the time interval (0.24 sec, 6.51 sec)
Step-by-step explanation:
The object is 'in the air' for all t such that h> 0. We need to find the roots of h = -16t^2 + 108t - 25 = 0. From the graph we see that both t values are positive. Once we find them, we subtract the smaller t from the larger t, which results in the length of time the object is in the air.
Use the quadratic formula to find the roots of h(t). The coefficients of t are {-16, 108, -25}, and so the discriminant b^2 - 4ac is
108² - 4(-16)(-25) = 11664 - 1600 = 10064, whose square root is 100.32.
Then the quadratic formula x = (-b ± √[b² - 4ac)/(2a) becomes
-108 ± 100.32 108 ± 100.32
t = ---------------------- = --------------------- = 3.375 ± 3.135
2(-16) 32
or t = 6.51 or t = 0.24 (both times expressed in seconds).
So, again, the object is in the air on the time interval (0.24 sec, 6.51 sec)
Answer:
A) 2x3 + 11x2 + 8x - 16.
Step-by-step explanation:
s(x).t(x) = (x + 4)( 2x2 + 3x - 4)
= x(2x2 + 3x - 4) + 4( 2x2 + 3x - 4)
= 2x3 + 3x2 - 4x + 8x2 + 12x - 16
= 2x3 + 11x2 + 8x - 16
Answer:
3 3/8
Step-by-step explanation:
1 3/4 + 1 5/8
We need to get a common denominator of 8
1 3/4 *2/2 + 1 5/8
1 6/8 + 1 5/8
I like to line them up vertically
1 6/8
1 5/8
---------------
2 11/8
But 11 is larger than 8 so we subtract 8/8 and add 1
2 11/8
+1 -8/8
---------------
3 3/8
