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Maslowich
3 years ago
15

Please help ASAP this is timed

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
5 0

Answer:

1.)616 in

2.)260 ft

3.) 744 mm

Step-by-step explanation:

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The MTC Theater holds 250 people, and last night's performance sold out! Children's tickets were $2.50 per ticket, while adults
olasank [31]

60 children tickets and 190 adult tickets were sold.

<u>Step-by-step explanation:</u>

Let the no. of adult tickets sold be 'a'

Let the no. of children tickets sold be 'c'

Total tickets sold = 250

Cost of 1 children ticket = $2.5

Cost of 1 adult ticket = $4

Total money collected= $910

Given that,

a + c = 250

a = 250 - c

4a + 2.5c = 910

Substitute a value

4(250 - c) + 2.5c = 910

1000 - 4c + 2.5c = 910

1000 - 1.5c = 910

-1. 5c = -90

1.5c = 90

c = 90/1.5

c = 60

a + c = 250

a + 60 = 250

a = 190

60 children tickets and 190 adult tickets were sold.

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3 years ago
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The energy at the screen is roughly equal to the product of the number of maxima, the peak intensity of a maximum, and the width
fomenos

Answer:

The width of the maxima is proportion with 1/N

Step-by-step explanation:

* Lets explain how to solve the problem

- If y varies directly with x (y ∝ x), then y = kx where k is the constant

 of variation

- If y varies inversely with x (y ∝ 1/x), then y = m/x where m is the

 constant of variation

* Lets solve the problem

- The energy at the screen is roughly equal to the product of the

  number of maxima, the peak intensity of a maximum, and the

  width of a maximum

∴ E = nIw, where E is the energy at the screen, n is the number of

  maxima, I is the peak intensity w is the width of a maxima

- As N increases, the number and location of the maxima will

 not change

∴ n is constant

- The peak intensity of the maxima will increase proportionally to N²

∴ I ∝ N²

∴ I = kN² ⇒ k is the constant of variation

- The total energy available increases proportionally to N

∴ E ∝ N

∴ E = mN ⇒ m is the constant of variation

* Lets substitute all of these in the equation of energy

∵ E = mN

∵ I = kN²

∴ mN = n(kN²)w ⇒ divide both sides by N

∴ m = nkNw

- Divide both sides by nkN

∴ m/nkN = w

∵ m , n , k are constant, then we replace them by the constant A,

   where A = m/nk

∴ A/N = w

∴ w = constant × 1/N

∴ w ∝ 1/N

∴ w is proportion with 1/N

* The width of the maxima is proportion with 1/N

5 0
3 years ago
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