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Artist 52 [7]
3 years ago
11

The following data represent scores on a pop quiz in a business statistics section. Suppose the data on quiz scores will be grou

ped into five classes. The width of the classes for a frequency distribution or histogram is the closest to ______.
Mathematics
1 answer:
ruslelena [56]3 years ago
8 0

Answer:

Taking data:

                         28 78 74 89 72

                         50 55 66 26 84

                         59 64 88 23 27

                         70 63 42 37 29

The answer is Width \ of\ class= 13

Step-by-step explanation:

As the data is not given in the question i'm guessing the data from the question i solved before

28 78 74 89 72

50 55 66 26 84

59 64 88 23 27

70 63 42 37 29

as taking the above data,

          Maximum\  value= 89

          Minimum\ vaue=23

          Number\ of\ classes\ scores\ are\ divided\ into =5\ classes

As we know for finding the width of class:

          Width\ of\ class = (max\ value - min\ value)/(\#\ of\  classes)

          Width = (89 - 23)/5 = 66/5

          Width = 13.2  ≈ 13

Note : By using the above given formula you can calculate the width of any data just by taking the maximum and minimum values of data and the number of classes the data is divided into.

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Help!!!! me please the first to answer will get brainliest!!!! please help me<br><br><br>​
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<h3>1 Answer: v = -130</h3>

=============================================================

Explanation:

Because we're given multiple choices to pick from, we can go through each to do trial and error.

For instance, if v = 52, then

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but that's a false statement since 4 is not smaller than -7. Use a number line to see this. You should have -7 to the left of 4, showing that -7 is the smaller value.

Because 4 < -7 is false, this means v/13 < -7 is false when v = 52. This rules out v = 52. You should find that v = 26 and v = -39 won't work for similar reasons.

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-------------------------------------------------

Another approach:

We have some unknown number v, and we're dividing by 13 to get the expression v/13. To undo this, we multiply both sides by 13

v/13 < -7

13*(v/13) < 13*(-7) .... multiply both sides by 13

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The value v = -130 is smaller than -91, so it satisfies v < -91. Therefore, v = -130 is a solution to the original inequality.

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