3 years ago

I need help I need help

Mathematics

2 answers:

vesna_86 [32]3 years ago

6 0

Answer:

Step-by-step explanation:

dimaraw [331]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Please help me with #'s 5&6

Fynjy0 [20]

$5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm\sqrt{-9}\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}$

$6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=\dfrac{25}{4}\to x-10=\pm\sqrt{\dfrac{25}{4}}\\\\x-10=-\dfrac{\sqrt{25}}{\sqrt4}\ \vee\ x-10=\dfrac{\sqrt{25}}{\sqrt4}\\\\x-10=-\dfrac{5}{2}\ \vee\ x-10=\dfrac{5}{2}\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}$

7 0

3 years ago

Simon and greg shared pencils in the ratio 7:5. if simon gives away 30 pencils and greg gets 30 more pencils, they will have the

Dafna1 [17]

Simon has 210 pencils
Greg has 150 pencils

7 0

3 years ago

Let f(x)=x^3 and g(x)= √x, and h(x)=x/3. Find each of the following: f(g(h(6)))

rewona [7]

Answer:

go from inside out.

h(x)=x/3

$(\sqrt{2})^{3}$ => h(6) = 6/3 = 2

g(x) = $\sqrt{x}$

=> g(h(6)) = g(2) = $\sqrt{2}$

f(x) = $x^{3}$

=> f(g(h(6))) = f( $\sqrt{2}$ ) = $(\sqrt{2} )^{3}$

6 0

3 years ago

Find y Solve the simultaneous equations 3x + 2y = 27 3x - Y = 9

lutik1710 [3]

Answer:

$y = 6$

Step-by-step explanation:

To find $y$ , we need to eliminate $x$ in this system of equations:

$3\cdot x + 2\cdot y = 27$ (1)

$3\cdot x - y = 9$ (2)

From (1) and (2):

$x = \frac{27-2\cdot y}{3}$

$x = \frac{9+y}{3}$

Then, we equalize both expressions and solve for $y$ :

$\frac{27-2\cdot y}{3} = \frac{9+y}{3}$

$27-2\cdot y = 9 + y$

$3\cdot y = 18$

$y = 6$

6 0

3 years ago

Write an algebraic expression for the phrase the sum of g and 3

Paraphin [41]

The sum of g and 3.

The sum of two values is added together.

g+3

You would add g to 3 since it is their sum the statement is asking for.

I hope this helps!
~kaikers

3 0

3 years ago

I need help I need help​

I need help I need help