All categories

1 year ago

CD player: $142.00Sales tax: 5.5%

Mathematics

1 answer:

zubka84 [21]1 year ago

6 0

The total amount paid by a customer who purchased a CD player at $142.00 and sales tax of 5.5% is $149.81

<h3>Sales tax</h3>

Cost of CD player = $142.00
Sales tax = 5.5%

Amount of sales tax = 5.5% of $142.00

= 5.5/100 × 142

= 0.055 × 142

= $7.81

Total amount paid by customers = Cost of CD player + Amount of sales tax

= $142.00 + $7.81

= $149.81

Learn more about sales tax:

brainly.com/question/1700984

#SPJ1

You might be interested in

WHAT'S THE ERROR? A student says 3(n- 5) is equal to 3n - 5. What's<br>the error?

inn [45]

Answer:

The student incorrectly used the Distributive property!

Step-by-step explanation:

The Distributive property says a(b+c)=ab+ac

In this problem the answer SHOULD be 3n-15, however the <u>student forgot to distribute the 3 to the -5</u>!

8 0

3 years ago

Read 2 more answers

How do you graph the equation Y = 4x + 2 and 4x - 3y = 12?

Pachacha [2.7K]

Answer:look below

Step-by-step explanation:

To graph y= 4x +2 plot the point (0,2) on the graph because the y-intercept is 2 then use the slope: 4 to find another point. Another point would be (1,6).

6 0

2 years ago

Can anyone help me pls ( if you can, can you do it on paper and post it with the answer)

Molodets [167]

Answer:

7=a

Step-by-step explanation:

look at image for step by step

4 0

2 years ago

Please help. Calculate the area of the shaded region in each figure use 3.14 for π and round to the nearest 10th if necessary

denpristay [2]

Answer: See below

Explanation:

Find the area of circle:

A = 3.14 x 5^2
A = 3.14 x 25
A = 78.5 cm^2

Find the area of rectangle:

A = 3 x 4
A = 12

Find area of shaded region:

A(shaded) = A(circle) - A(rectangle)
A = 78.5 - 12 = 66.5 cm^2

5 0

2 years ago

Find the exact value of cot(15degrees) using half angle formulas?

liubo4ka [24]

Double angle (or half angle, depending how you look at it) identities:

$\cos^2\dfrac x2=\dfrac{1+\cos x}2$

$\sin^2\dfrac x2=\dfrac{1-\cos x}2$

$\implies\cot^2\dfrac x2=\dfrac{\cos^2\frac x2}{\sin^2\frac x2}=\dfrac{1+\cos x}{1-\cos x}$

So we have

$\cot^215^\circ=\dfrac{1+\cos30^\circ}{1-\cos30^\circ}=\dfrac{1+\frac{\sqrt3}2}{1-\frac{\sqrt3}2}$

$\implies\cot^215^\circ=7+4\sqrt3$

$\implies\cot15^\circ=\sqrt{7+4\sqrt3}=2+\sqrt3$

Note that when taking the square root, we should take into account that that could yield two possible solutions, but we know $\cos15^\circ>0$ and $\sin15^\circ>0$ , so it's also the case that $\cot15^\circ>0$ .

Also, the reason we have equality in the last step can be explained like so:

$7+4\sqrt3=4+4\sqrt3+3=4+4\sqrt3+(\sqrt3)^2=(2+\sqrt3)^2$

(not unlike the process used to complete the square)

8 0

3 years ago

Read 2 more answers

CD player: $142.00Sales tax: 5.5%​

CD player: $142.00Sales tax: 5.5%