How do you solve 12x+4y=40?

The local oil changing business is very busy on Saturday mornings and is considering expanding. A national study of similar busi

eimsori [14]

Answer:

$t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714$

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131

Rejection Zone: $t_{calculated}$ or $t_{calculated}>2.131$

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=4.2$ represent the sample mean

$s=1.4$ represent the sample standard deviation

n=16 represent the sample selected

$\alpha=0.05$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different from 3.6, the system of hypothesis would be:

Null hypothesis: $\mu = 3.6$

Alternative hypothesis: $\mu \neq 3.6$

If we analyze the size for the sample is < 30 and we know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714$

Critical values

On this case since we have a bilateral test we need to critical values. We need to use the t distribution with $df=n-1=16-1=15$ degrees of freedom. The value for $\alpha=0.05$ and $\alpha/2=0.025$ so we need to find on the t distribution with 15 degrees of freedom two values that accumulates 0.025 of the ara on each tail. We can use the following excel codes:

"=T.INV(0.025,15)" "=T.INV(1-0.025,15)"

And we got $t_{crit}=\pm 2.131$

So the decision on this case would be:

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131

Rejection Zone: $t_{calculated}$ or $t_{calculated}>2.131$

Conclusion

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

3 0

4 years ago

Can someone please help me am failing

vichka [17]

All together it equals (of the number of hours he does in a week)
45 because 6 plus 9 is 15 and 15 multipled by 3 is 45 makes sense becuase .. 6 +3 is 9 and 9 +9 is 18 2 weeks equals 14 days 18 subtracted by 14 equals 2 which 45 subtracted by 2 is 43 and that's the esact number of hours he works 43 in a week.

7 0

4 years ago

An antelope is being chased across the savannah by a hungry lion. The lion runs at a constant speed. How might the antelope use

tatyana61 [14]

Answer:

you cannot answer this without a screen shot

Step-by-step explanation:

6 0

3 years ago

Give an example of an equation of a line that is parallel to y=3?

SOVA2 [1]

Answer:

y = 2

Step-by-step explanation:

Hope this helped

7 0

3 years ago

Write 7,004,000 in scientific notation.

MAXImum [283]

<span>7,004,000 in scientific notation.
=</span>7.004 x 10^6
as 7 is the first non zero digit
so decimal jumbed 6 numbers from right to left and exponent will be positive
option A is correct
hopr this helps

6 0

3 years ago