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densk [106]
4 years ago
9

The next two questions (Questions 7 and 8) refer to the following information: A Canadian study measuring depression level in te

ens (as reported in the Journal of Adolescence, vol. 25, 2002) randomly sampled 112 male teens and 101 female teens, and scored them on a common depression scale (higher score representing more depression). The researchers suspected that the mean depression score for male teens is higher than for female teens, and wanted to check whether data would support this hypothesis. If μ1 and μ2 represent the mean depression score for male teens and female teens respectively, which of the following is the appropriate pair of hypotheses in this case? (i) H0: μ1−μ2=0 Ha: μ1−μ2<0 (ii) H0: μ1−μ2>0 Ha: μ1−μ2=0 (iii) H0: μ1=μ2 Ha: μ1>μ2 (iv) H0: μ1−μ2=0 Ha: μ1−μ2>0 (v) Both (iii) and (iv) are correct.
Mathematics
1 answer:
Sav [38]4 years ago
6 0

Answer:

v- Both (iii) and (iv) are correct

Step-by-step explanation:

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Awarding road contracts. A state Department of Transportation (DOT) recently claimed that each of five bidders received equal co
Sveta_85 [38]

Answer:

a) Hence, the probability of this event occurring if, in fact, the DOT's claim is true

= 3/10 = 0.3

Step-by-step explanation:

a) The concept applied here is combinatorics ; nCr = n!/(n - r)!r!

we are told that out of 5bidders, Three of the bidders were large construction conglomerates

and two were small specialty contractors.

selecting two recipients with tree of the bidders were large construction conglomerates 3C2

= 3!/(3-2)!2!

= 3

Similarly, selecting the two small casualty contractor from the total of 5bidders = 5C2

= 5!/(5-2)!2!

= 10

Hence, the probability of this event occurring if, in fact, the DOT's claim is true

= 3/10 = 0.3

b) if DOTs claim is not true ( probability of failure) = 1 - 0.3

= 0.7 , this value implies that the probability 0.3 is largely compatible and a compliment of the 0.7 and as such it is consistent with the DOTs claim that the selection was random.

7 0
3 years ago
S t are positive integers
Sindrei [870]

Given:

The expanded form of (x+s)(x-t) is x^2+Kx-40.

Where, s, t, K are positive integers.

To find:

The smallest possible value of K.

Solution:

The expanded form of (x+s)(x-t) is x^2+Kx-40. It means,

(x+s)(x-t)=x^2+Kx-40

x^2-tx+sx-st=x^2+Kx-40

x^2+(s-t)x-st=x^2+Kx-40

On comping both sides, we get

K=s-t              ...(i)

K is a positive integer if s>t.

And

st=40

The factor pairs of 40 are (1,40), (2,20), (4,10), (5,8), (8,5), (10,4), (20,2) and (40,1).

Since s>t, therefore the possible values for (s,t) are (8,5), (10,4), (20,2) and (40,1).

Using (i), find the value of K for each factor pair.

K=8-5=3  

K=10-4=6      

K=20-2=18          

K=40-1=39          

Therefore, the smallest possible value of K is 3.

3 0
3 years ago
Please help!! image is below i would really appreciate it
Maurinko [17]

Answer:

3 mi

Step-by-step explanation:

c = 3√2 ÷ √2 = 3

-------

8 0
3 years ago
Expanded form of<br>a 54896<br>​
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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