The director of student health decides to test every student on campus for tuberculosis. If there are 3000 students out of which only 50 have tuberculosis and the probability of a false positive on the test is 0.008 and a false negative is 0.15, what is the probability that a person who tested positive actually has TB?
1 answer:
Answer: the probability that a person who tested positive actually has TB is 0.64
Step-by-step explanation:
lets say
T : has tuberculosis
+ : test results +ve
- : test result is -ve
so given that
P(+ITc) = 0.008
P(-ITc) = 0.15
P(T) = 50/3000 = 1/60
P(Tc) = 1 - P(T) = 1 - 1/60 = 59/60
Now required probability
= P(TI+)
P(T∩+) / P(+)
= P(T) × P(+IT) / [[P(T) × P(+IT)] + [(P(Tc) × P(+ITc)]
= P(T) × {1-P(-IT)] / [[P(T) × [1-P(-IT)] + [(P(Tc) × P(+ITc)]
WE SUBSTITUTE
= { 1/60 × (1-0.15) } / [1/60 × (1 - 0.15)] + [(59/60) × 0.008]
= (0.0167 × 0.85) / [(0.0167 × 0.85) + (0.9833 × 0.008)]
= 0.01417 / 0.02206
= 0.6423 ≈ 0.64
∴ the probability that a person who tested positive actually has TB is 0.64
You might be interested in
Answer:
2r(x^2-6)(x^2+6)
Step-by-step explanation:
2x^4r-72r=2r(x^4-36)=2r(x^2-6)(x^2+6)
Answer:
I belive its C not 100%
Step-by-step explanation:
Answer:
(x+2)(x2-2x+4).
Step-by-step explanation:
We know that volume of a bar of soap=2*4*0.5----> 4 in³ <span>A bar of soap is sold for $3 individually </span>so $3/4-----> 0.75 $/in³ <span>A three-pack of the same soap costs $8 so $8*(3*4)----> 0.67 $/in</span>³ <span>if you buy the three-pack you save-----> [0.75-0.67]=0.08 $/in</span>³the answer is $0.08
Answer:
What you are looking at is a scalene triangle!
Step-by-step explanation:
By definition scalene triangles are triangles where each side is a different length... hope this one helps you!